I need help! What is the value of t?
2 answers:
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<u>Answer: </u>
The point slope form of the line that passes through (-8,2) and is parallel to a line with a slope of -8 is 8x + y + 62 = 0
<u>Solution: </u>
The point slope form of the line that passes through the points and parallel to the line with slope “m” is given as
--- eqn 1
Where “m” is the slope of the line.
are the points that passes through the line.
From question, given that slope “m” = -8
Given that the line passes through the points (-8,2).Hence we get
By substituting the values in eqn 1, we get the point slope form of the line which is parallel to the line having slope -8 can be found out.
y-2=-8(x-(-8))
On simplifying we get
y – 2 = -8(x +8)
y – 2 = -8x -64
y – 2 +8x +64 = 0
8x + y +62 = 0
Hence the point slope form of given line is 8x + y +62 = 0
The graph of the linear equation can be seen in the image below.
<h3>How to complete the table?</h3>
Here we have the linear equation:
y = -4x + 8
And we want to find 3 ordered pairs, to do so, we need to evaluate x in different values.
if x = 0 then:
y = -4*0 + 8 = 8
So we have the ordered pair (0, 8).
if x = 1 then:
y = -4*1 + 8 = 4
Then we have the ordered pair (1, 4)
If x = 2 then:
y = -4*2 + 8 = 0
Then we have the ordered pair (2, 0).
Now that we have these 3 ordered pairs, we can graph them in a coordinate axis and then connect them with a line, we will get something like the graph below.
That is the graph of our linear equation:
If you want to learn more about linear equations:
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