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ololo11 [35]
3 years ago
5

Astronomers were trying to find the weight of six planets - Mars, Venus, Pluto, Jupiter, Mercury and Saturn. The number of plane

ts lighter than Mars was equal to the number of planets heavier than Venus. Saturn was heavier than Mars and Mercury was heavier than Pluto. Venus was lighter than Mars. Saturn was not the heaviest planet.
Mathematics
1 answer:
Bezzdna [24]3 years ago
3 0

Answer:

Step-by-step explanation:

Astronomers were trying to find the weight of six planets - Mars, Venus, Pluto, Jupiter, Mercury and Saturn. The number of planets lighter than Mars was equal to the number of planets heavier than Venus. Saturn was heavier than Mars and Mercury was heavier than Pluto. Venus was lighter than Mars. Saturn was not the heaviest planet.

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Sure Blame the answers
iren2701 [21]

Answer: For the model one it’s option 1 and for the other one it’s 10,000

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
The sum of two numbers is 8 if one number is subtracted from the other the result is -4
Delvig [45]
A + b = 8
a - b = -4

a = b - 4
(b - 4) + b = 8
2b - 4 = 8
2b = 12
b = 6
a + 6 = 8
a = 2

a = 2
b = 6

2 + 6 = 8
2 - 6 = -4
3 0
3 years ago
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1 At the annual hotdog eating contest, James eats 32 hotdogs in 60 seconds. At this rate, how long would it take James to eat 48
VLD [36.1K]

Answer:

90 seconds

Step-by-step explanation:

If James eats 32 hotdogs in 60 seconds, we want to find how long it would take James to eat 48 hotdogs.

We can use proportion to solve this problem.

If 32:60, then 48:x.

Since it will required more seconds to eat 48 hotdogs, 32 will divide.

If more, less divides.

Therefore

x =  \frac{48 \times 60}{32}

x = 90

Therefore it will take James 90 seconds if he eats at the same rate

5 0
3 years ago
A. 21<br> b. 15<br> c. 19<br> d. 17
Nezavi [6.7K]

Answer:

Step-by-step explanation:

If the radius of K is 16, and the length of IJ is 1, then the length of JK has to be 15, since 15 + 1 = 16

6 0
3 years ago
5. A solid has a circle of radius r as its base. All sections of the solid perpendicular to the diameter along the x-axis are is
AleksandrR [38]

Answer:

 \frac{16r^3}{3}

Step-by-step explanation:

In this cross sections problem, we can integrate from -r to +r (so that the integral covers the entire base of the solid).

\int\limits^r_a {2(x^2+r^2 )} \, dx

The formatting for the integral did not let me put -r on the lower bound, so i replaced it with a, just know that a represents -r here.

Evaluating the integral gives use that it is equal to;

\frac{16r^3}{3}

Caution: this answer may not meet your needs, but this is the answer I have come up with with the given information.

If you found this answer helpful please consider leaving 5 stars, giving it a like, or if you asked this question, mark this answer as Brainliest. Thanks!

4 0
3 years ago
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