Answer:
7π cm² ≈ 22.0 cm²
Step-by-step explanation:
The shaded area is the difference between the area of Circle B and the areas of Circle C and Circle O. That is, those white areas are subtracted from the area of Circle B to get the shaded area.
The formula for the area of a circle is
A = πr²
Using this, we find ...
Circle B area = π(3 cm)² = 9π cm²
Circle C area = Circle O area = π(1 cm)² = π cm²
Then the shaded area is ...
Shaded Area = Circle B area - Circle C area - Circle O area
= (9π cm²) - (π cm²) - (π cm²)
= 7π cm² ≈ 22 cm²
<span>Diagonals of a rhombus are perpendicular and bisect each other. This means this rhombus is composed of four right triangles with legs of length 6 cm and 8 cm, with their hypotenuses forming the perimeter of the rhombus. The Pythagorean theorem a^2+ b^2 = c^2 can be used to find the length of the hypotenuse. 6^2+8^2 = 36+64 = 100. The square root of 100 is 10, so the length of a side of the rhombus is 10 cm.</span>
$15.00/11 pounds = $1.3636 per pound$20.00/16 pounds = $1.25 per pound 1.363636 - 1.25 = $0.113636 per pound, less
1.363636 × 20 = $27.27 original price for 20lb
Jamie can take one of the three different buses to and from school bus A ,B, and C. she randomly get just one person in the morning and another one on the way home this gift list same space of outcomes the answer is
C. BC
Did the quiz
The second-degree polynomial function f(x) that has a lead coefficient of 4 and roots 5 and 2 is f(x) = 4x² -28x + 40. The correct option is the last option f(x)=4x²-28x+40
<h3>Quadratic equation</h3>
From the question, we are to determine which second-degree polynomial function f(x) has a lead coefficient of 4 and roots 5 and 2
To determine this, we will use the given roots to determine the equation
The roots are 5 and 2
Thus
x = 5 and x = 2
x - 5 = 0 and x - 2 = 0
Therefore,
(x -5)(x -2) = 0
Distributing
x(x -2) -5(x -2) = 0
x² -2x -5x + 10 = 0
x² -7x + 10 = 0
Now, multiplying through by 4, we get
4x² -28x + 40 = 0
Thus, the function becomes f(x) = 4x² -28x + 40
Hence, the second-degree polynomial function f(x) that has a lead coefficient of 4 and roots 5 and 2 is f(x) = 4x² -28x + 40. The correct option is the last option f(x)=4x²-28x+40
Learn more on Quadratic Equation here: brainly.com/question/19257086
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