Final result : -3
Step by step solution :Step 1 : 3 - a Simplify ————— 21 Equation at the end of step 1 : (a - 3) (3 - a) ——————— ÷ ——————— 7 21 Step 2 : a - 3 Simplify ————— 7 Equation at the end of step 2 : (a - 3) (3 - a) ——————— ÷ ——————— 7 21 Step 3 : a-3 3-a Divide ——— by ——— 7 21
3.1 Dividing fractions
To divide fractions, write the divison as multiplication by the reciprocal of the divisor :
a - 3 3 - a a - 3 21 ————— ÷ ————— = ————— • ——————— 7 21 7 (3 - a)
3.2 Rewrite (3-a) as (-1) • (a-3) Canceling Out : 3.3 Cancel out (a-3) which now appears on both sides of the fraction line.
Final result : -3
Here is the answer! Hope it helps! (C.)
Answer:
D. Linear
The answer is negative linear, because when it incresing from 0 to 1 to 2 to 3 (year) it always deacreasing in the value($).
Answer:
- x + y ≤ 600
- 5x +7y ≥ 3500
- it is possible
Step-by-step explanation:
a) We can write two inequalities, one for the number of tickets, and one for the necessary revenue.
x + y ≤ 600 . . . . . . . limit imposed by available seating
5x +7y ≥ 3500 . . . . required revenue to meet expenses
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b) For x = 330, the first inequality puts one limit on y:
330 +y ≤ 600
y ≤ 270
And the second inequality puts another limit on y:
5(330) +7y ≥ 3500
7y ≥ 1850 . . . . subtract 1650
y ≥ 264.3 . . . . divide by 7
The number of tickets that must be sold to meet expenses is 265, which is less than the number that can be sold, 270. It is possible to meet expenses.
