To find 1/10 of a number you need (1/10)*number, or number/10
number/10=0.0003
number=0.0003*10=0.003
Ray is 12 miles from home.
Let x be Ray's distance from home. His distance is one leg of a right triangle; 5, Rosa's distance from home, is the other. The hypotenuse, the distance between them, is 1 more than Ray's distance from home, or x+1. Using the Pythagorean theorem,
5²+x²=(x+1)²
25+x²=(x+1)(x+1)
Multiplying the binomials, we have
25+x²=x*x+1*x+1*x+1*1
25+x²=x²+1x+1x+1
25+x²=x²+2x+1
Subtracting x² from both sides,
25 = 2x+1
Subtracting 1 from both sides,
24 = 2x
Divide both sides by 2, and we have
12 = x
Ray is 12 miles from home.
Answer: C
Step-by-step explanation:
Answer:
(f + g)(x) = 3x² + (7/3)x - 8
Step-by-step explanation:
To find (f + g)(x), you need to add both the f(x) and g(x) equations together.
f(x) = x/3 - 2 ..... which is equal to ... f(x) = (1/3)x - 2
g(x) = 3x² + 2x - 6
(f + g)(x) = ((1/3)x - 2) + (3x² + 2x - 6) <----- Add both equations
(f + g)(x) = 3x² + (1/3)x + 2x - 2 - 6 <----- Rearrange (2 = 6/3)
(f + g)(x) = 3x² + (7/3)x - 8 <----- Simplify similar terms
Answer:
C. Test for Goodness-of-fit.
Step-by-step explanation:
C. Test for Goodness-of-fit would be most appropriate for the given situation.
A. Test Of Homogeneity.
The value of q is large when the sample variances differ greatly and is zero when all variances are zero . Sample variances do not differ greatly in the given question.
B. Test for Independence.
The chi square is used to test the hypothesis about the independence of two variables each of which is classified into number of attributes. They are not classified into attributes.
C. Test for Goodness-of-fit.
The chi square test is applicable when the cell probabilities depend upon unknown parameters provided that the unknown parameters are replaced with their estimates and provided that one degree of freedom is deducted for each parameter estimated.
