A+b is 5+2 which equals 7
c=3 but 7 cannot be divided by 3.
which would be why this cannot be evaluated
Answer:
(3ab^3+2c^6)(9a^2b^6-6ab^3c^6+4c^12)
Step-by-step explanation:
Given:
Polynomial 27a^3 b^9+8c^18
Factoring the given polynomial
27a^3b^9 can be written as
=3^3.a^3.b^3^3
=(3ab^3)^3
Also 8c^18 can be written as
=2^3.c^6^3
=(2c^6)^3
Hence Polynomial 27a^3 b^9+8c^18 can be written as
=(3ab^3)^3+(2c^6)^3
Applying sum of cubes formula i.e. a^3 + b^3=(a+b)(a^2 – ab + b^2)
=(3ab^3+2c^6)(9a^2b^6-6ab^3c^6+4c^12) !
Answer:
omg ikr
Step-by-step explanation:
very sad 2
First the two angles are equal to one another so take note of that.
Now setup the equation which will be
x+90=4x
Now get rid of alike terms
So subtract x from both sides
90=3x
Now divide 90 by 3
x=30
