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daser333 [38]
3 years ago
11

Colton wants to buy a video game system in 3 months. The video game system cost $396. If he saves the same amount each month, ho

w much will he have to save each month
Mathematics
1 answer:
Margarita [4]3 years ago
3 0
20........................
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Help me with this please and thank you!! :)
Ann [662]

Answer:

Step-by-step explanation:

  • A \cap C denotes the set of elements in both A and C, which is \{20, 24, 28\}.
  • B^{C} denotes the complement of set B, which is the set of all elements that are in the universal set that are not in set B. In this case, this set is \{3, 4, 5, 6, 8, 11, 13, 16, 17, 19, 20, 22, 23, 24, 25, 26, 27, 28\}
7 0
1 year ago
Order the numbers from least to greatest<br><br>-3,9,0,-11,7,-6
igor_vitrenko [27]

-11 ,-3, -6, 0, 7, 9 I hope im right


7 0
3 years ago
The following prices, in dollars, of 7.5-cubic-foot refrigerators were recorded from a random sample. 314 305 344 283 285 310​ 3
Mariana [72]

Answer:

t=\frac{310.9-300}{\frac{31.09}{\sqrt{10}}}=1.109      

The degrees of freedom are given by:

df=n-1=10-1=9  

And the p value would be given by:

p_v =P(t_{9}>1.109)=0.148  

Since the p value is higher than the significance level of 0.05 we don't have enough evidence to conclude that the true mean is significantly higher than $300 because we FAIL to reject the null hypothesis.

Step-by-step explanation:

Information given

314 305 344 283 285 310​ 383​ 285​ 300​ 300

We can calculate the sample mean and deviation with the following formula:

\bar X =\frac{\sum_{i=1}^n X_i}{n}

s =\sqrt{\frac{\sum_{i=1}^n (x_i -\bar X)^2}{n-1}}

\bar X=310.9 represent the sample mean      

s=31.09 represent the standard deviation for the sample      

n=10 sample size      

\mu_o =300 represent the value to test

\alpha=0.05 represent the significance level

t would represent the statistic

p_v represent the p value

Hypothesis to test

We want to verify if the true mean is greater than 300, the system of hypothesis would be:      

Null hypothesis:\mu \leq 300      

Alternative hypothesis:\mu > 300      

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)      

Replacing the info given we got:

t=\frac{310.9-300}{\frac{31.09}{\sqrt{10}}}=1.109      

The degrees of freedom are given by:

df=n-1=10-1=9  

And the p value would be given by:

p_v =P(t_{9}>1.109)=0.148  

Since the p value is higher than the significance level of 0.05 we don't have enough evidence to conclude that the true mean is significantly higher than $300 because we FAIL to reject the null hypothesis.

6 0
3 years ago
A minimum temperature of -4.44°C was recorded at a lake. A minimum temprature of 23.3°C was recorded later on the same day. Dete
GuDViN [60]

Answer:

27.74 is the difference

Step-by-step explanation:

23.3° C - (-4.44° C)

23.3 + 4.44

27.74

5 0
2 years ago
NEED HELP ASAP PLEASE
Alik [6]
Sure what is it???????
8 0
3 years ago
Read 2 more answers
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