Answer:
The equation of the straight line is x - 2y +6 =0
Step-by-step explanation:
<u>Explanation:</u>-
Given a point ( 2, 4) and slope m =
The equation of the straight line passing through the point and having slope 'm'
y - y₁ = m ( x - x₁)
y - 4 = ( x - 2)
2( y -4) = ( x-2)
2 y - 8 = x -2
x - 2 y - 2 + 8 =0
x - 2y + 6 =0
The equation of the straight line is x - 2y +6 =0
Answer:
The solution is (3,13) and (-1,-3). So none of the mentioned options is correct.
Step-by-step explanation:
Given that
Now, by susbstituting the value of 'y' from equation i to equation ii, we get
Now by factorization, equation iii can be written as
x = 3 and x = -1
By putting the values of x in equation i, we get
y = 4(3) + 1
y = 12 +1
y = 13
and
y = 4(-1) + 1
y = -4 +1
y = -3
Therefore, the solution is (3,13) and (-1,-3). So none of the mentioned options is correct.