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2 years ago

If a scale is 1:5000 and the model length is 15 cm how much cm is the real length?

Mathematics

1 answer:

meriva2 years ago

6 0

Answer:

250

Step-by-step explanation:

cm in the equation.

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When heated and metal barn creases in line from 1.25 m to 1.262 m calculate percentage increase the correct one decimal place. C

Misha Larkins [42]

Answer:

0.96%

Step-by-step explanation:

Well the easy way to do this is

1.262

- - - - - - - x 100 = 100.96%

1.25

( this is just saying, now the thing is 100.96% of it original size)

So now they are asking the increase, so just simply take

100.96 - 100

= 0.96%

4 0

2 years ago

What’s the answer ??? V/8=5-3

sergeinik [125]

Answer:

V=16

Step-by-step explanation:

V/8=5-3

V/8=2

V/8*8=2*8

V=16

7 0

3 years ago

Monomials. Please help. I have a test (m^8)^5

cricket20 [7]

Answer:

$m^{40}$

Step-by-step explanation:

$(m^8)^5=m^{8*5} =m^{40}$

Hope this helps!

8 0

2 years ago

If a barrel averages 50 pounds and a crate 160 pounds, write an inequality that describes when x barrels and y crates will caus

irakobra [83]

Answer:

https://iepa.org.au/network-news/it

Step-by-step explanation:

that link is answer

6 0

3 years ago

How do you solve this

AlladinOne [14]

Answer:

domain: all terms are defined for all real numbers
solution: x = 6

Step-by-step explanation:

Rewrite the equation as a single exponential. After taking the log, the solution becomes obvious.

$5^{x-2}-7^{x-3}=7^{x-5}+11\cdot 5^{x-4}\\\\5^{x-2}-11\cdot 5^{x-4}=7^{x-3}+7^{x-5}\\\\5^{x-2}(1-11\cdot 5^{-2})=7^{x-3}(1+7^{-2})\\\\5^{x-2}\dfrac{14}{25}=7^{x-3}\dfrac{50}{49}\\\\1=\dfrac{2\cdot 7^{x-3}5^4}{2\cdot 5^{x-2}7^3}=\left(\dfrac{7}{5}\right)^{x-6}\\\\0=(x-6)\log(1.4)\\\\x=6$

6 0

3 years ago