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atroni [7]
3 years ago
12

Find the value of x. then find the angle measures of the triangle...​

Mathematics
1 answer:
amid [387]3 years ago
3 0

Answer:

x = 35

105°, 40°, and 35°

Step-by-step explanation:

A triangle has 180°

180° - 40° = 140°

3x + x = 4x

4x = 140

4x /4 = 140 /4

x = 35

------------------

x * 3 = 105°

40°

x = 35°

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Helppppppppppppppppppppppppppppppppppppppp?
alexgriva [62]

Answer:

Step-by-step explanation:

GHJ looks like it on 112 degrees.

IHJ is an acute angle so smaller than 90 degrees. I cant see the numbers there but I'm guessing its about 68 degrees.

GHJ + IHJ= 180

they should equal 180 degrees when added together.

6 0
3 years ago
Can some please help me with this one it would be much appreciated
kherson [118]

πAnswer:

Therefore, the area of a sector of a circle would be 13.5π square units.              

Step-by-step explanation:

Given

  • r=9 mi
  • Ф = 60°

The area of a sector of a circle is:

A = π r² Ф/360

A = π (9)² 60/360

A = π 81 * 1/6

A = 13.5π square units

Therefore, the area of a sector of a circle would be 13.5π square units.                        

7 0
3 years ago
a carpenter has a wooden stick that is 84 centimeters long. She cuts off 25% from the end of the stick. then she cuts the remain
Karo-lina-s [1.5K]
She cuts off 21 cm. this leaves 63cm. cut into 6 equal pieces gives 10.5 cm pcs
3 0
3 years ago
Please answer the following question. Also please answer if you actually know it.
Iteru [2.4K]

Given : f(x)= 3|x-2| -5

f(x) is translated 3 units down and 4 units to the left

If any function is translated down then we subtract the units at the end

If any function is translated left then we add the units with x inside the absolute sign

f(x)= 3|x-2| -5

f(x) is translated 3 units down

subtract 3 at the end, so f(x) becomes

f(x)= 3|x-2| -5 -3

f(x) is translated   4 units to the left

Add 4 with x inside the absolute sign, f(x) becomes

f(x)= 3|x-2 + 4| -5 -3

We simplify it and replace f(x) by g(x)

g(x) = 3|x + 2| - 8

a= 3, h = -2 , k = -8



5 0
3 years ago
Could someone do all the problems and/or check my work?
MArishka [77]
11. You’ve done it correctly

12. Let x^2=y
y^2+13y+40=0
(y+8)(y+5)=0
y=8, 5
Since y=x^2
x^2=8 x^2=5
x=+/-√5 x= +/-2√2

13. x^4-x^2-x^2-8=0
x^4-2x^2-8=0
let x^2=y
Y^2-2y-8=0
(y-4)(y+2)=0
y=4, -2
Since y=x^2
X^2=4 X^2=-2
X= +/- 2 This wouldn’t be a real solution

14. It’s pretty much the same process, just substitute y in for x^2. If you’re confused feel free to ask and I can do it, or you can put it through Photomath

15. You’re on the right track so I’m just going to continue from where you left off
x^2(4x+5)-4(x+5)=0
(x^2-4)(4x+5)=0
x= +/- 2 4x=5
x=5/4 or 1 1/4

Hope this helped :)
8 0
3 years ago
Read 2 more answers
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