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3 years ago

Please help! I will give brainliest and 5 stars!

Mathematics

1 answer:

Ierofanga [76]3 years ago

7 0

Answer:

(A.) x = y - 4

Step-by-step explanation:

All you need to do is subtract the 4 from both sides, giving you the final equation as x = y - 4.

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In 1960, the average cost of a gallon of milk was $0.49. In 1985, the average cost of a gallon of milk was $2.26. Which of the f

USPshnik [31]

Answer: its C

Step-by-step explanation:

HOPE THIS HELPS

3 0

3 years ago

Someone please help me !

Leni [432]

Answer:

Can't tell if it went through...

1. Shop A = 2x

2. Shop B = 2x - 580

3. Total = Shop A + Shop B

1949 = 2x + 2x - 580

4. Combine like terms

2x + 2x = 4x

1949 = 4x - 580

5. Add 580 to both sides (to remove -580 from right side)

1949 + 580 = 4x - 580 + 580

2529 = 4x

6. Divide both sides by 4 (to get x)

2529 / 4 = 4x / 4

632.25 = x

7. Shop A = 2x

2 * 632.25 = 1264.50

Shop A = 1264.50

8. Shop B = 2x - 580

2 * 632.25 - 580 = 684.50

Shop B = 684.50

Check: Shop A + Shop B = 1949

1264.50 + 684.50 = 1949

Shop A = 1264.50

Shop B = 684.50

Step-by-step explanation:

8 0

3 years ago

What is the length of the curve with parametric equations x = t - cos(t), y = 1 - sin(t) from t = 0 to t = π? (5 points)

zzz [600]

Answer:

B) 4√2

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Parametric Differentiation

Integration

Integrals
Definite Integrals
Integration Constant C

Arc Length Formula [Parametric]: $\displaystyle AL = \int\limits^b_a {\sqrt{[x'(t)]^2 + [y(t)]^2}} \, dx$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle \left \{ {{x = t - cos(t)} \atop {y = 1 - sin(t)}} \right.$

Interval [0, π]

Step 2: Find Arc Length

[Parametrics] Differentiate [Basic Power Rule, Trig Differentiation]: $\displaystyle \left \{ {{x' = 1 + sin(t)} \atop {y' = -cos(t)}} \right.$
Substitute in variables [Arc Length Formula - Parametric]: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{[1 + sin(t)]^2 + [-cos(t)]^2}} \, dx$
[Integrand] Simplify: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx$
[Integral] Evaluate: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx = 4\sqrt{2}$