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3 years ago

Please help! I will give brainliest and 5 stars!

Mathematics

1 answer:

Ierofanga [76]3 years ago

7 0

Answer:

(A.) x = y - 4

Step-by-step explanation:

All you need to do is subtract the 4 from both sides, giving you the final equation as x = y - 4.

You might be interested in

What is the range of the function f(x) = = 3x + 2 in the domain -2

djyliett [7]

Answer:

The range is:

{-4, 1, 2, 5, 8}

Step-by-step explanation:

Given the function

$f(x)=3x+2$

We know that the domain of a function is the set of input or argument values for which the function is real and defined.

As the domain interval -2 ≤ x ≤ 2

i.e. the values in the domain = {-2, -1, 0, 1, 2}

We also know that the range of a function is the set of values of the dependent variable for which a function is defined.

As the domain interval -2 ≤ x ≤ 2

Putting all the x-values in the domain interval in the function

putting x=-2 in the function

$f(x)=3x+2$

$f(-2)=3(-2)+2=-6+2=-4$

putting x=-1 in the function

$f(x)=3x+2$

$f(-1)=3(-1)+2=-3+2=1$

putting x=0 in the function

$f(x)=3x+2$

$f(0)=3(0)+2=0+2=2$

putting x=1 in the function

$f(x)=3x+2$

$f(1)=3(1)+2=3+2=5$

putting x=2 in the function

$f(x)=3x+2$

$f(2)=3(2)+2=6+2=8$

Thus, when we put the domain values, the corresponding range values are:

x y

-2 -4

-1 1

0 2

1 5

2 8

Therefore, the range is:

{-4, 1, 2, 5, 8}

8 0

2 years ago

Which order pair could represent the location of point h

Rus_ich [418]

What does the work look like first

5 0

3 years ago

The statistical difference between a process operating at a 5 sigma level and a process operating at a 6 sigma level is markedly

Svet_ta [14]

Answer:

True

Step-by-step explanation:

A six sigma level has a lower and upper specification limits between $\\ (\mu - 6\sigma)$ and $\\ (\mu + 6\sigma)$ . It means that the probability of finding no defects in a process is, considering 12 significant figures, for values symmetrically covered for standard deviations from the mean of a normal distribution:

$\\ p = F(\mu + 6\sigma) - F(\mu - 6\sigma) = 0.999999998027$

For those with defects operating at a 6 sigma level, the probability is:

$\\ 1 - p = 1 - 0.999999998027 = 0.000000001973$

Similarly, for finding no defects in a 5 sigma level, we have:

$\\ p = F(\mu + 5\sigma) - F(\mu - 5\sigma) = 0.999999426697$ .

The probability of defects is:

$\\ 1 - p = 1 - 0.999999426697 = 0.000000573303$

Well, the defects present in a six sigma level and a five sigma level are, respectively:

$\\ {6\sigma} = 0.000000001973 = 1.973 * 10^{-9} \approx \frac{2}{10^9} \approx \frac{2}{1000000000}$

$\\ {5\sigma} = 0.000000573303 = 5.73303 * 10^{-7} \approx \frac{6}{10^7} \approx \frac{6}{10000000}$

Then, comparing both fractions, we can confirm that a 6 sigma level is markedly different when it comes to the number of defects present:

$\\ {6\sigma} \approx \frac{2}{10^9}$ [1]

$\\ {5\sigma} \approx \frac{6}{10^7} = \frac{6}{10^7}*\frac{10^2}{10^2}=\frac{600}{10^9}$ [2]

Comparing [1] and [2], a six sigma process has 2 defects per billion opportunities, whereas a five sigma process has 600 defects per billion opportunities.

8 0

3 years ago

Please help me! in need of help due tomorrow!

julsineya [31]

Answer:

Step-by-step explanation:

(1). A = π r²

A = 4 π

Area of shaded region is $\frac{4\pi *260}{360}$ = $\frac{26}{9} \pi$ or $\frac{26\pi }{9}$