Rearrange the equation to make g the subject.SHOW ALL WORKING OUT!f+4(g-h)=x

Mathematics

2 answers:

In-s [12.5K]2 years ago

7 0

Answer:

The answer is

$g = \frac{x - f}{4} + h$

Step-by-step explanation:

f + 4(g - h) = x

Send f to the right side of the equation

That's

4(g - h) = x - f

Divide both sides by 4

That's

g - h = (x - f)/ 4

Send h to the right side of the equation

We have the final answer as

Hope this helps you

Leokris [45]2 years ago

3 0

Answer:

Step-by-step explanation:

f+4(g-h)=x

4(g-h)=x-f

g-h=(x-f)/4

g=((x-f)/4)+h

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The admission fee at an amusement park is $4.00 for children and $5.60 for adults. On a certain day, 284 people entered the park

miv72 [106K]

4c+5.6d=1360
Let
Children (c)=x
Adults (d)=284-x

4x+5.6 (284-x)=1360
Solve for x
4x+1590.4-5.6x=1360
4x-5.6x=1360-1590.4
-1.6x=-230.4
X=230.4÷1.6
X=144 children

284−144=140 adults

3 0

3 years ago

2(a³+b²+11)+1(3+a³+b+11)

Ann [662]

Answer:

$2(a^3+b^2+11)+1(3+a^3+b+11)=3a^3+2b^2+b+36$

Step-by-step explanation:

I assume that you need simplification of the given expression.

The given expression is:

$2(a^3+b^2+11)+1(3+a^3+b+11)$

Using distributive property and multiplying 2 inside the parenthesis and 1 inside the other parenthesis. This gives,

$2(a^3+b^2+11)=2\times a^3+2\times b^2+2\times 11\\2(a^3+b^2+11)=2a^3+2b^2+22\\\\1(3+a^3+b+11)=1\times 3+1\times a^3+1\times b+1\times 11\\1(3+a^3+b+11)=3+a^3+b+11=a^3+b+14$