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2 years ago

Which situation below would represent a negative rate of change:

Mathematics

1 answer:

uranmaximum [27]2 years ago

3 0

Answer: John's situation

Step-by-step explanation:

Hi, to answer this question we have to write an equation for each situation.

John’s situation:

The amount of money that John has (y) is equal to his school account (40) minus the product of the number of days (x) and the amount he spends per day( 3)

y =40-3x

As days pass by, John has less money (negative rate of change)

Judy's situation

The amount of money that Judy has in her savings account (y) is equal to the product of the number of days (x) and the amount he saves per day (20/2)

y = x (20/2)

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2 years ago

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1 year ago

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In 1990, the population of Boston, Massachusetts was 574,283. In 2000, the population was 589,141. What is the percent of change

MrMuchimi

Answer:

Percent of change in population is $2.6$ %

Step-by-step explanation:

Given population of Boston is $574,283$ measured in year $1990$ .

And population of Boston in year $2000$ is $589,141$ .

We need to find percent of change in population.

So, percent change $=\frac{New\ population-Old\ population}{Old\ population}\times100$ %

Here old population is $574,283$ and new population is $589,141$

Plugging these value in formula we get,

Percent change $=\frac{589,141-574,283}{574,283}\times100\\\\=\frac{14858}{574,283}\times100=0.0258\times100\\\\=2.587$

Rounding to nearest tenth 2.6%

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