Answer:
Function sparse code is
def sparse(a):
rl = []
cl = []
for i in range(0,len(a)):
rl.append(a[i][1])
cl.append(a[i][2])
r = max(rl)
c = max(cl)
s = []
k = 0
for i in range(0,r+1):
s.append([])
for j in range(0,c+1):
if (i==a[k][1]) & (j == a[k][2]):
s[i].append(a[k][0])
k = k+1
else:
s[i].append(0)
return s
def main():
k = sparse([[3,1,2],[4,5,3]])
print(k)
if __name__ == '__main__':
main()
Explanation:
Please see attachment for output
Technology helps business professionals, keep more organized, communicate better, and effectively keeps businesses secure. Technology helps keep employee information and business paper<span> work more organized using</span>computers<span> and </span>software<span>; while making it easier to communicate with employee's using e-mail and memo's. With better alarm systems, camera's and online banking, security measures are endless. </span>
I believe the answer is <span>annual maintenance
</span><span>annual maintenance refers to the system maintenance that being done at a regular time period (most commonly done at least every 6 month)
This is really necessary in order to detect potential virus/malware that would compromise the information within your computer.</span>
A row, which is also called a tuple.
To convert the inputs to dollars and cents, we make use of a combination of multiplication and addition.
The program written in Python where comments are used to explain each line is as follows:
<em />
<em>#This gets input for the number of quarters</em>
quarters = int(input("Quarters: "))
<em>#This gets input for the number of dimes</em>
dimes = int(input("Dimes: "))
<em>#This gets input for the number of nickels</em>
nickels= int(input("Nickels: "))
<em>#This gets input for the number of pennies</em>
pennies= int(input("Pennies: "))
<em>#This converts the amount to dollars and cents</em>
dollars = quarters * 0.25 + dimes * 0.10 + nickels * 0.05 + pennies * 0.01
<em>#This prints the amount to 2 decimal places</em>
print("Amount ${:.2f}".format(dollars))
Read more about Python programs at:
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