A village experienced 2% population growth, compounded continuously, each year for 10 years. At the end of the 10 years, the pop
2 answers:
Answer:
The initial population at the beginning of the 10 years was 129.
Step-by-step explanation:
The population of the village may be modeled by the following function.
In which P is the population after t hours, is the initial population and r is the growth rate, in decimal.
In this problem, we have that:
.
So
The initial population at the beginning of the 10 years was 129.
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Answer:
- B) One solution
- The solution is (2, -2)
- The graph is below.
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Explanation:
I used GeoGebra to graph the two lines. Desmos is another free tool you can use. There are other graphing calculators out there to choose from as well.
Once you have the two lines graphed, notice that they cross at (2, -2) which is where the solution is located. This point is on both lines, so it satisfies both equations simultaneously. There's only one such intersection point, so there's only one solution.
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To graph these equations by hand, plug in various x values to find corresponding y values. For instance, if you plugged in x = 0 into the first equation, then,
y = (-3/2)x+1
y = (-3/2)*0+1
y = 1
The point (0,1) is on the first line. The point (2,-2) is also on this line. Draw a straight line through the two points to finish that equation. The other equation is handled in a similar fashion.
