Answer:
I think the answer is 109.752 ♡
Step-by-step explanation:
Answer:
i want to say the answer is A
Step-by-step explanation:
Answer:
A. 2564 cm^2
Step-by-step explanation:
There are two triangles (Which both are the same) and three different rectangles.
1. Let's solve the area of the triangles first!
Formula: bh(1/2)
10(26)(1/2)
130
2. Now, let's multiply by 2 since there's two of them:
130(2) = 260
3. So, we got 260. Let's find the area of the three rectangles!
Formula: bh
Rectangle A: 28(36) = 1008
Rectangle B: 10(36) = 360
Rectangle C: 26(36) = 936
4. Add the area of the triangles and the rectangles!
260 + 1008 + 360 + 936 = 2564
So the surface area is 2564 cm^2
Hope this helps! <3
Answer:
8.12
Step-by-step explanation:
we first multiply 8 by 12 and we will get 96 as our answer
<u>Answer:</u>
are two roots of equation 
<u>Solution:</u>
Need to solve given equation using quadratic formula.

General form of quadratic equation is 
And quadratic formula for getting roots of quadratic equation is

In our case b = -1 , a = -3 and c = -3
Calculating roots of the equation we get

Since
is equal to -35, which is less than zero, so given equation will not have real roots and have complex roots.
