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Hunter-Best [27]

2 years ago

9

If the average rate of travel is 100 miles per day, about how long would it take to

1 answer:

krok68 [10]2 years ago

5 0

Answer:

Distance, rate and time problems are a standard application of linear equations. When solving these problems, use the relationship rate (speed or velocity) times time equals distance.

Explanation:

For example, suppose a person were to travel 30 km/h for 4 h. To find the total distance, multiply rate times time or (30km/h)(4h) = 120 km.

The problems to be solved here will have a few more steps than described above. So to keep the information in the problem organized, use a table. An example of the basic structure of the table is below:

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Half x s for s equals 3/10

777dan777 [17]

1/2 x s, where s equals 3/10 means,

(1/2) x (3/10) which will give (3/20)

You simply multiply the numerators to get 3 and the denominators to get 20.

8 0

3 years ago

(5,2) (8,2), (8,5) and (?,?)

Luba_88 [7]

<h2>Answer:</h2><h2>(5,5)</h2><h2 /><h2>Hope this helps!!</h2><h2></h2>

6 0

2 years ago

Gravel is being dumped from a conveyor belt at a rate of 20 ft3 /min and its coarseness is such that it forms a pile in the shap

pantera1 [17]

Answer:

The height of the pile is increasing at the rate of $\mathbf{ \dfrac{20}{56.25 \pi} \ \ \ \ \ ft/min}$

Step-by-step explanation:

Given that :

Gravel is being dumped from a conveyor belt at a rate of 20 ft³ /min

i.e $\dfrac{dV}{dt}= 20 \ ft^3/min$

we know that radius r is always twice the diameter d

i.e d = 2r

Given that :

the shape of a cone whose base diameter and height are always equal.

then d = h = 2r

h = 2r

r = h/2

The volume of a cone can be given by the formula:

$V = \dfrac{\pi r^2 h}{3}$

$V = \dfrac{\pi (h/2)^2 h}{3}$

$V = \dfrac{1}{12} \pi h^3$

$V = \dfrac{ \pi h^3}{12}$

Taking the differentiation of volume V with respect to time t; we have:

$\dfrac{dV}{dt }= (\dfrac{d}{dh}(\dfrac{\pi h^3}{12})) \times \dfrac{dh}{dt}$

$\dfrac{dV}{dt }= (\dfrac{\pi h^2}{4} ) \times \dfrac{dh}{dt}$

we know that:

$\dfrac{dV}{dt}= 20 \ ft^3/min$

So;we have:

$20= (\dfrac{\pi (15)^2}{4} ) \times \dfrac{dh}{dt}$

$20= 56.25 \pi \times \dfrac{dh}{dt}$

$\mathbf{\dfrac{dh}{dt}= \dfrac{20}{56.25 \pi} \ \ \ \ \ ft/min}$

The height of the pile is increasing at the rate of $\mathbf{ \dfrac{20}{56.25 \pi} \ \ \ \ \ ft/min}$

8 0

3 years ago

|-3+(-1)|= simply the expression

Andreyy89

Answer:

4

Step-by-step explanation:

First, solve in the brackets,

-3+(-1)

-3-1

-4

Since it is absolute value, take the minus sign away,

therefore the answer is 4

8 0

3 years ago

For the equation, decide if it is always true or never true.<br><br> 2(x + 3) = 5x + 6 − 3x

SCORPION-xisa [38]

Answer:

always true

Step-by-step explanation:

Given

2(x + 3) = 5x + 6 - 3x ← distribute left side

2x + 6 = 2x + 6

Since both sides are equal then any real value of x is a solution.

Thus the equation is always true

3 0

2 years ago