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Sati [7]
3 years ago
12

What's does variables mean

Chemistry
2 answers:
Soloha48 [4]3 years ago
5 0
Factor that can be controlled changed or measured in an experiment.
Elodia [21]3 years ago
3 0
<span>Variable definition. A variable is a quantity that may change within the context of a mathematical problem or experiment. Typically, we use a single letter to represent a variable. The letters x, y, and z are common generic symbols used for variables.</span>
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You've just solved a problem and the answer is the mass of an electron, me=9.11×10−31kilograms. How would you enter this number
mihalych1998 [28]

The mass of an electron can be expressed in the box as \boxed{{m_e} = 9.1 \times {{10}^{ - 31}}{\text{ kg}}}.

Further explanation:

Atom is the smallest particle that can be present in any element. It is also known as the building unit of matter. Each atom has a central part that is known as the atomic nucleus. There are three subatomic particles that constitute the atom. These particles are protons, neutrons, and electrons. The atomic nucleus consists of protons and neutrons, both are collectively called nucleons. Electrons revolve around the nucleus of an atom in definite orbits.

Protons are positively charged subatomic particles, electrons are negatively charged and neutrons have no charge. Since electrons carry a unit negative charge, these create an electric field around them. These also participate in nuclear reactions. The mass of an electron \left( {{m_e}} \right) is 9.1 \times {10^{ - 31}}{\text{ kg}}, that of protons is 1.6726219 \times {10^{ - 27}}{\text{ kg}} and that of neutrons is 1.674927471 \times {10^{ - 27}}{\text{ kg}}. The electrons are responsible for chemical properties of elements. The distribution and arrangement of electrons is used to predict whether the element will be inert or reactive.

Therefore the required answer is \boxed{{m_e} = 9.1 \times {{10}^{ - 31}}{\text{ kg}}}.

Learn more:

  1. Component of John Dalton’s atomic theory: brainly.com/question/2357175
  2. Basis of investigation for the scientists: brainly.com/question/158048

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Atomic structure

Keywords: atom, matter, atomic nucleus, proton, electron, neutron, subatomic particle, nuclear reactions, electric field, reactive, inert.

4 0
4 years ago
Which process would require the least amount of energy? Which process would require the least amount of energy? the process for
oee [108]

Answer:

The process of the first ionization energy

Explanation:

The ionization energy is the energy required to remove one electron for one isolated atom at the gas phase. The first electron to be removed is the valence electron which is far away from the nuclei. Because of that, this electron suffers a less attraction force.

For the second ionization energy, the electron will be closer to the nuclei, so it is more attracted, then a large amount of energy is necessary to remove it. For the third, the amount of energy will be larger. So, the first ionization energy requires the least amount of energy.

3 0
4 years ago
Determine the number of sub shells and orbital in the fifth main shell​
Black_prince [1.1K]

Answer: maximum no. is 8 in 5th shell

Explanation:

6 0
3 years ago
Given the lattice energy of NaBr = 736 kJ/mol, the ionization energy of Na = 496 kJ/mol and the electron affinity of Br = −325 k
mars1129 [50]

Answer : The value of \Delta H^o for the reaction is, -565 kJ/mol

Explanation :  

The formation of sodium bromide is,

Na(g)+Br(g)\overset{\Delta H^o}\rightarrow NaBr(s)

\Delta H^o = enthalpy of the reaction

The steps involved in the reaction are:

(1) Conversion of gaseous sodium atoms into gaseous sodium ions.

Na(g)\overset{\Delta H_I}\rightarrow Na^{+1}(g)

\Delta H_I = ionization energy of sodium = 496 kJ/mol

(2) Conversion of gaseous bromine atoms into gaseous bromine ions.

Br(g)\overset{\Delta H_E}\rightarrow Br^-(g)

\Delta H_E = electron affinity energy of bromine = -325 kJ/mol

(3) Conversion of gaseous cations and gaseous anion into solid sodium bromide.

Na^+(g)+Br^-(g)\overset{\Delta H_L}\rightarrow NaBr(s)

\Delta H_L = lattice energy of sodium bromide = -736 kJ/mol

To calculate the \Delta H^o for the reaction, the equation used will be:

\Delta H^o=\Delta H_I+\Delta H_E+\Delta H_L

Now put all the given values in this equation, we get:

\Delta H^o=496kJ/mole+(-325kJ/mole)+(-736kJ/mole)

\Delta H^o=-565kJ/mole

Therefore, the value of \Delta H^o for the reaction is, -565 kJ/mol

7 0
3 years ago
What is the chemical bond between mg and p?
masya89 [10]

Answer:

Electronegativity

Explanation:

6 0
4 years ago
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