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borishaifa [10]
3 years ago
12

A ball is moving at a speed of 6.70 m/s. If the kinetic energy of the ball is 3.10 J, what is the mass of the ball?​

Chemistry
1 answer:
Anni [7]3 years ago
7 0

Answer:

<h2>0.14 kg</h2>

Explanation:

The mass of the ball can be found by using the formula

m =  \frac{2k}{ {v}^{2} }  \\

v is the velocity

k is the kinetic energy

From the question we have

m =  \frac{2(3.10)}{ {6.70}^{2} }  =  \frac{6.20}{44.89}  \\  = 0.138115...

We have the final answer as

<h3>0.14 kg</h3>

Hope this helps you

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Number of hydrogen atom(s) in water (H2O)
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Answer:

Maybe

Explanation:

the number of hydrogen atom in water is 2..

hope it helps

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which change in the temperature of the one gram sample of water would cause the greatest increase in average kinetic energy of i
LenaWriter [7]

Maybe about in the 50ths


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75As3- what is it’s protons, neutrons, and electrons?
Aneli [31]

Answer:

Atomic Particles

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7 0
2 years ago
What is the boiling point of 0.464 m lactose in water? (Kb of water = 0.512 oC/m). Enter your answer to 3 decimal places.
kirill [66]

Answer:

Boiling point for the solution is 100.237°C

Explanation:

We must apply colligative property of boiling point elevation

T° boiling solution - T° boiling pure solvent = Kb . m

m = molalilty (a given data)

Kb = Ebulloscopic constant (a given data)

We know that water boils at 100°C so let's replace the information in the formula.

T° boiling solution - 100°C = 0.512 °C/m . 0.464 m

T° boiliing solution = 0.512 °C/m . 0.464 m + 100°C → 100.237 °C

3 0
3 years ago
If 30 ml of water containing 15 mg of salicylate is extracted with 30 ml of chloroform, 2.59 mg of salicylate remains in the wat
In-s [12.5K]

Answer:

Distribution coefficient: 4.79

Explanation:

Distribution coefficient is the ratio between equilibrium concentration of non-aqueous phase and aqueous phase where both solvents are inmiscible. The equation for the problem is:

Distribution coefficient: Concentration in chloroform / Concentration in Water

<em>Concentration in water: 2.59mg / 30mL = 0.08633mg/mL</em>

<em>Concentration in chloroform: (15mg-2.59mg) / 30mL = 0.4137mg/mL</em>

<em />

Distribution coefficient: 0.4137mg/mL / 0.08633mg/mL

<h3>Distribution coefficient: 4.79</h3>
8 0
3 years ago
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