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algol [13]
3 years ago
13

Colton has a 1/20 probability of winning the race. Logan has a 15% probability of winning. Who has the greater chance of winning

?
A Colton
B Logan
C They have an equal chance
Mathematics
1 answer:
LiRa [457]3 years ago
4 0

Answer:

Logan has the greater probability of winning

Step-by-step explanation:

Colton=1/20

=0.05

So the probability of Colton is 0.05

Logan=15%

=15/100

=0.15

So the probability of Logan is 0.15

When comparing the two,it was observed that the Logan has greater probability of winning

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gavmur [86]
Step 1: <span>Set up the long division.
 
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4| 3 2 2 0

Step 2: </span><span>Calculate 32 ÷ 4, which is 8.
       
</span>  __ 8____
4| 3 2 2 0
    3 2

Step 3: Bring down 20, so that 20 is large enough to be divided by 4.

__ 8____
4| 3 2 2 0
    3 2
_________
          2 0

Step 4: Calculate<span> 20 ÷ 4, which is 5.
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</span>  ________
4| 3 2 2 0
    3 2
  ________
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Step 5: Therefore,<span> 3,220 ÷ 4 = 805.

The answer is 805

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3 0
4 years ago
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Ugo [173]
Answer: D) y= 14/17x - 4/17
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3 years ago
Three security cameras were mounted at the corners of a triangles parking lot. Camera 1 was 110 ft from camera 2, which was 137
Nata [24]

Answer:

<em>Camera 2nd has to cover the maximum angle, i.e. </em>78.70^\circ.

Step-by-step explanation:

Please have a look at the triangular park represented as a triangle \triangle ABC with sides

a = 110 ft

b = 158 ft

c = 137 ft

1st camera is located at point C, 2nd camera at point B and 3rd camera at point A respectively.

We can use law of cosines here, to find out the angles \angle A, \angle B, \angle C

As per Law of cosine:

cos C = \dfrac{a^{2}+b^2-c^2 }{2ab}\\cos B = \dfrac{a^{2}+c^2-b^2 }{2ac}\\cos A = \dfrac{b^{2}+c^2-a^2 }{2bc}

Putting the values of a,b and c to find out angles \angle A, \angle B, \angle C.

cos C = \dfrac{110^{2}+158^2-137^2 }{2\times 110 \times 158}\\\Rightarrow cos C = \dfrac{12100+24964-18769 }{24760}\\\Rightarrow cos C =0.526\\\Rightarrow C = 58.24^\circ

cos B = \dfrac{110^{2}+137^2-158^2 }{2\times 110 \times 137}\\\Rightarrow cos B = \dfrac{12100+18769 -24964}{30140}\\\Rightarrow cos B = \dfrac{5905}{30140}\\\Rightarrow cos B =0.196\\\Rightarrow B = 78.70^\circ

cos A = \dfrac{158^{2}+137^2-110^2 }{2\times 158 \times 137}\\\Rightarrow cos A = \dfrac{24964+18769-12100}{43292}\\\Rightarrow cos A = \dfrac{31633}{43292}\\\Rightarrow cos A = 0.731\\\Rightarrow A = 43.05^\circ

<em>Camera 2nd has to cover the maximum angle</em>, i.e. 78.70^\circ.

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Answer:

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Answer:

Step-by-step explanation:

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