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2 years ago

Yuhgghghgvggvgvvvvvvv

Mathematics

1 answer:

Mazyrski [523]2 years ago

3 0

Its freeee thing ? Yayyyyyy

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Factor by finding the GCF:<br> 8x-10

lys-0071 [83]

Answer:

The GCF is 2

Step-by-step explanation:

Hope this helps!!

3 0

2 years ago

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Mike has a net spendable income of $1,400. He decides to set up a budget before looking for an apartment or a car. He sets up hi

Shtirlitz [24]

C.) Mike is using the minimum recommended percentages for food, housing, and transportation. The costs are likely to exceed the expenses in each category.

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2 years ago

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Hamburger is sold 2 pounds for $4. If Alicia buys 10 pounds of hamburgers, how much will she pay?

raketka [301]

Answer:

Step-by-step explanation:

you multyply 4 by 10 to get 40 or add 4 10 times

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1 year ago

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Find the general solution to 1/x dy/dx - 2y/x^2 = x cos x, y(pi) = pi^2

Finger [1]

Answer:

$\frac{y}{x^2}=\sin x+\pi$

Step-by-step explanation:

Consider linear differential equation $\frac{\mathrm{d} y}{\mathrm{d} x}+yp(x)=q(x)$

It's solution is of form $y\,I.F=\int I.F\,q(x)\,dx$ where I.F is integrating factor given by $I.F=e^{\int p(x)\,dx}$ .

Given: $\frac{1}{x}\frac{\mathrm{d} y}{\mathrm{d} x}-\frac{2y}{x^2}=x\cos x$

We can write this equation as $\frac{\mathrm{d} y}{\mathrm{d} x}-\frac{2y}{x}=x^2\cos x$

On comparing this equation with $\frac{\mathrm{d} y}{\mathrm{d} x}+yp(x)=q(x)$ , we get $p(x)=\frac{-2}{x}\,\,,\,\,q(x)=x^2\cos x$

I.F = $e^{\int p(x)\,dx}=e^{\int \frac{-2}{x}\,dx}=e^{-2\ln x}=e^{\ln x^{-2}}=\frac{1}{x^2}$ { formula used: $\ln a^b=b\ln a$ }

we get solution as follows:

$\frac{y}{x^2}=\int \frac{1}{x^2}x^2\cos x\,dx\\\frac{y}{x^2}=\int \cos x\,dx\\\\\frac{y}{x^2}=\sin x+C$

{ formula used: $\int \cos x\,dx=\sin x$ }

Applying condition: $y(\pi)=\pi^2$

$\frac{y}{x^2}=\sin x+C\\\frac{\pi^2}{\pi}=\sin\pi+C\\\pi=C$

So, we get solution as :

$\frac{y}{x^2}=\sin x+\pi$

4 0

2 years ago

Find perimeter and area

Iteru [2.4K]

I dunno if im right but i believe the area is 182 and the perimeter is 54 but im highly not confident about the perimeter though

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2 years ago

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