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Free_Kalibri [48]
3 years ago
12

(a) A fire station is to be located along a road of length A, A<

Mathematics
1 answer:
Marrrta [24]3 years ago
6 0

Answer:

Answer in picture attached

Step-by-step explanation:

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6700 dollars is placed in an account with an annual interest rate of 8.25%. How much will be in the account after 28 years, to t
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At the end of 28 years, there will be 22,083.2 dollars in the account.

Step-by-step explanation:

Step 1; First we must calculate how much interest there is in total over 28 years. The annual interest rate is 8.25% i.e. 8.25% of 6,700 dollars which equals 552.75 dollars. As the years' pass, more and more will be put into the account due to interest. After 28 years, there will be an interest of 229.6% (8.25% per year * 28 years)of the initial amount.

Step 2; We must find the money due to interest and add it with the money that was put in initially. The interest amount is 2.296 times the 6,700 dollars which was put in. The interest equals 15,383.2 dollars. With this, the initial 6,700 dollars is added which comes to a total of 22,083.2 dollars

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Use information in the diagram to determine the height of the tree. The diagram is not to scale
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The answer is 60........
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Whoever guesses not only the song but the singer will get brainliest if there are any absurd answers they will be deleted.
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Answer: "See Me Fall" by Ro Ransom

Step-by-step explanation:

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Easy Sample Ap graphing 50pts! (Easy points!!) (ASAP) (URGENT) (Please check my other questions)​ Please
snow_lady [41]

Answer:

a)  See attachment 1.

b)  t² and D

c)  See attachment 2.

d)  g = 9.8 m/s² (1 d.p.)

Step-by-step explanation:

<h3><u>Part (a)</u></h3>

See attachment 1.  The line of best fit is shown in red.

<h3><u>Part (b)</u></h3>

The quantities the student should graph in order to produce a <u>linear relationship</u> between the two quantities are t² and D.

<h3><u>Part (c)</u></h3>

Make a table of values of t² and D:

\begin{array}{|l|l|l|l|l|l|}\cline{1-6} \rm t^2& 0.0196& 0.1024& 0.2116 & 0.3481& 0.3969\\\cline{1-6} \rm D & 0.10 & 0.50& 1.00 & 1.70 & 2.00\\\cline{1-6}\end{array}

<u>Plot</u> a graph of D against t² and draw a line of best fit (see attachment 2).

<h3><u>Part (d)</u></h3>

From inspection of the graph, the line of best fit passes through the origin (0, 0) and (0.1024, 5.0).  Therefore, use these two points to find the slope of the line:

\textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{0.5-0}{0.1024-0}=4.8828125...\:\rm m/s^2

Therefore:

\rm \implies \dfrac{1}{2}g=4.8828125...\:\rm m/s^2

\rm \implies g=2 \cdot 4.8828125...\:\rm m/s^2

\rm \implies g=9.8\:\rm m/s^2\:(1\:d.p.)

5 0
2 years ago
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