Question

Find the measure of angle P in the triangle below.

Answer 1

Answer:

Step-by-step explanation:

Sin (angle p) = 48/60 = 4/5 = 0.8

angle p = sin∧-1 0.8 = 53.13010235

Answer 2

Answer:

53.13°

Step-by-step explanation:

It the given triangle PQR,

$p=48,q=60,r=36$

Cosine formula:

$\cos A=\dfrac{b^2+c^2-a^2}{2bc}$

We need to find the measure of angle P.

$\cos P=\dfrac{q^2+r^2-p^2}{2qr}$

Substitute the given values.

$\cos P=\dfrac{(60)^2+(36)^2-(48)^2}{2(60)(36)}$

$\cos P=\dfrac{2592}{4320}$

$\cos P=0.6$

$P=\cos^{-1}(0.6)$

$P\approx 53.13$

Hence, the measure of angle P is 53.13 degrees.