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andreyandreev [35.5K]
3 years ago
14

Find the measure of angle P in the triangle below.

Mathematics
2 answers:
kykrilka [37]3 years ago
6 0

Answer:

Step-by-step explanation:

Sin (angle p) = 48/60 = 4/5 = 0.8

angle p = sin∧-1 0.8 = 53.13010235

GalinKa [24]3 years ago
6 0

Answer:

53.13°

Step-by-step explanation:

It the given triangle PQR,

p=48,q=60,r=36

Cosine formula:

\cos A=\dfrac{b^2+c^2-a^2}{2bc}

We need to find the measure of angle P.

\cos P=\dfrac{q^2+r^2-p^2}{2qr}

Substitute the given values.

\cos P=\dfrac{(60)^2+(36)^2-(48)^2}{2(60)(36)}

\cos P=\dfrac{2592}{4320}

\cos P=0.6

P=\cos^{-1}(0.6)

P\approx 53.13

Hence, the measure of angle P is 53.13 degrees.

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