Answer: I think the Independent variable is the amount of feed additive that the farmer gives to his cows.
Explanation:
I'm pretty sure it's carbohydrates
Answer:
Replicated chromosomes at metaphase I = 66
Sister chromatids at metaphase I = 66 x 2 = 132
Sister chromatids at prophase II = 66
Chromosomes in each sperm cells = 33
Explanation:
Metaphase I of meiosis I would have 66 replicated chromosomes in the testicular cells of the bird. Each of the replicated chromosomes would have two sister chromatids. So, a total of 66 replicated chromosomes would have 66 x 2 = 132 sister chromatids.
Due to segregation of homologous chromosomes towards opposite poles in anaphase I, each daughter cell formed by the end of meiosis I would have 33 replicated chromosomes. So, each of the daughter cells would have a total 33 x 2 = 66 sister chromatids at prophase II.
Since meiosis II maintains the chromosome number, each sperm cell formed by the end of meiosis II would have 33 chromosomes.
1. A cell must duplicate its DNA so the daughter cell with have the same about of identical DNA
2. Mitosis
Hope this helps
B. ATP is hydrolyzed and turns into ADP
ATP --> ADP + P = HYDROLYSIS
ADP + P --> ATP = PHOSPHORYLATION
