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r-ruslan [8.4K]
3 years ago
10

When you form general ideas and rules based on your experiences and

Mathematics
1 answer:
Usimov [2.4K]3 years ago
7 0

Answer:

C. Induction

Step-by-step explanation:

Induction is a form of reasoning, in which a person forms general ideas and rules based on his or her experiences and observations. It is simply, the process of arriving at a conclusion based on a set of observations, which is not a valid method of proof.

Therefore, when one forms general ideas and rules based on his or her experiences and observations, we call that form of reasoning, inductive reasoning.

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Log3 a/3 = ??????????????????????????
Naddik [55]
We have that
<span>Log3 a/3
</span>Rewrite log3(a/3) using the change of base <span>formula

we know that
</span>The change of base rule can be used if a and b are greater than 0 and not equal to 1, and x is greater than 0<span>.
</span>so
loga(x)=<span>logb(x)/<span>logb<span>(a)
</span></span></span>Substitute in values for the variables in the change of base <span>formula
</span>
in this problem
b=10
a=3
x=a/3

log3(a/3)=[log (a/3)]/[log (3)]

the answer is
[log (a/3)]/[log (3)]

8 0
4 years ago
Read 2 more answers
Plz help plz only I need the answer
TEA [102]

Answer:

The second one

Step-by-step explanation:

4 0
3 years ago
Pls show work! questions on pic
Lena [83]

Answer:

a.(10,23)

b.(7,30)

e.(20,20)

Step-by-step explanation:

We are given that

x=Width of garden

y=Length of garden

According to question

x\geq 5

y\geq 20

Perimeter of rectangle=2(x+y)

Where x=Width  of rectangle

y=Length of rectangle

Fencing used =2(x+y)

2(x+y)\leq 80

First we change inequality  into equality

x=5...(1)

y=20...(2)

2(x+y)=80

x+y=40...(3)

Substitute x=0 in equation (3)

y=40

Substitute y=0  in equation (3)

x=40

Substitute x=0 and y=0 in equation (3)

2(x+y)\leq 80

0\leq 80

It is true. Therefore, the  shaded region below the line.

0\geq 5

0\geq 20

These are false equation .Therefore, the shaded region above the line.

Substitute x=5 in equation (3)

5+y=40

y=40-5=35

Substitute y=20 in equation (3)

x+20=40

x=40-20=20

Intersection point of equation (1) and (3) is (5,35) and intersect point of equation (2) and (3) is (20,20).

Now,

a.(10,23)

Substitute in

2(x+y)\leq 80

2(10+23)\leq 80

66\geq 80

10>5 and 23>20

it satisfied all inequality.

Hence, it is a solution.

b.(7,30)

7>5

30>20

2(7+30)=74

it satisfied all inequality.

Hence, it is a solution.

c.(18,25)

18>5

25>20

2(18+25)=86>80

It does not satisfied third inequality

Hence, it is not a solution.

d.(8,35)

8>5

35>20

2(8+35)=86>80

It does not satisfied third inequality

Hence, it is not a solution.

e.(20,20)

2(20+20)=80

20>5

20=20

it satisfied all inequality.

Hence, it is a solution.

4 0
3 years ago
A graph is shown below. What is the constant and proportionality for the line on the graph below? A:-3/2 B:-2/3 C:2/3 D:3/2
baherus [9]

Answer: -3/2

Explanation: Start from -3 and go over 2 then where u stopped go down 3 from there and over 2 again and u will get -3/2

8 0
3 years ago
Read 2 more answers
For the rhombus, what are the slopes of the two diagonals? DO NOT introduce any new variables.
Jobisdone [24]

The slopes of the two diagonals of the rhombus are: A. b - f/a - e and -a + e/b - f.

<h3>What is the Slope of a Line Segment?</h3>

To find the slope, the formula used is: change in y/change in x.

If two lines are perpendicular to each other, their slope values will be negative reciprocals.

<h3>What is the Diagonals of a Rhombus?</h3>

In a rhombus, the two diagonals in the rhombus bisects each other at angle 90 degrees. This means that the two diagonals of a rhombus are perpendicular to each other. Therefore, the slope of the diagonals of any rhombus would be negative reciprocals.

The slope of the diagonals of the rhombus given would therefore be negative reciprocals to each other.

Given two endpoints of one of the diagonals as:

(a, b) = (x1, y1)

(e, f) = (x2, y2)

Slope (m) = change in y / change in x = b - f/a - e

The negative reciprocal of b - f/a - e is -a + e/b - f.

Therefore, the slopes of the two diagonals are: A. b - f/a - e and -a + e/b - f.

Learn more about the slopes of diagonals of a rhombus on:

brainly.com/question/3050890

#SPJ1

5 0
2 years ago
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