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Serjik [45]
3 years ago
5

What is the interquartile range of this data? A.6 B.7 C.8 D.9

Mathematics
1 answer:
Butoxors [25]3 years ago
6 0
Hello!

To find the interquartile range, subtract the value of the upper quartile from the value of the lower quartile. 

33 - 25 = 8

The interquartile range is 8. Hope I helped! :3
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What is the value of x?<br><br><br><br> 3x−8=8x+4/2<br><br><br><br> Enter your answer in the box.
bekas [8.4K]

Answer:

x = -2

Step-by-step explanation:

3x -8 =8x +4/2

3x -8 =8x +2

3x -3x -8 = 8x -3x +2 (subtract 3x both sides )

-8 = 5x +2

-8-2 =5x+2 -2  (subtract 2 both sides )

-10 =5x

-10/5 = 5x/5 (divide 5 both sides)

-2 = x

3 0
3 years ago
A sheet of paper has a perimeter of 39 inches. If the width of the paper is 8.5 inches, what is the length of the sheet of paper
tatiyna
Hello :
the perimeter is P: P=2(W+L)        W : the width      L: <span>the length
    2(8.5 +L</span>) = 39
17+2L = 39
2L =22
L= 11
7 0
3 years ago
Find the constant of variation if an employee earns $175 for 15 hours work.
RUDIKE [14]

Answer:

11.67

Step-by-step explanation:

6 0
3 years ago
WILL MARK BRAINLIEST <br><br> what is the domain of (f/g) (x)?
tatyana61 [14]

Given that f(x) = \sqrt{7-x} and g(x) = \sqrt{x + 2}, we can say the following:

\Bigg(\dfrac{f}{g}\Bigg)(x) = \dfrac{f (x)}{g(x)} = \dfrac{\sqrt{7 - x}}{\sqrt{x+2}}


Now, remember what happens if we have a negative square root: it becomes an imaginary number. We don't want this, so we want to make sure whatever is under a square root is greater than 0 (given we are talking about real numbers only).


Thus, let's set what is under both square roots to be greater than 0:

\sqrt{7 - x} \Rightarrow 7 - x \geq 0 \Rightarrow x \leq 7

\sqrt{x + 2} \Rightarrow x + 2 \geq 0 \Rightarrow x \geq -2


Since both of the square roots are in the same function, we want to take the union of the domains of the individual square roots to find the domain of the overall function.

x \leq 7 \,\,\cup x \geq -2 = \boxed{-2 \leq x \leq 7}


Now, let's look back at the function entirely, which is:

\Bigg( \dfrac{f}{g} \Bigg)(x) = \dfrac{\sqrt{7 - x}}{\sqrt{x+2}}

Since \sqrt{x + 2} is on the bottom of the fraction, we must say that \sqrt{x + 2} \neq 0, since the denominator can't equal 0. Thus, we must exclude \sqrt{x + 2} = 0 \Rightarrow x + 2 = 0 \Rightarrow x = -2 from the domain.


Thus, our answer is Choice C, or \boxed{ \{ x | -2 < x \leq 7 \}}.


<em>If you are wondering why the choices begin with the x | symbol, it is because this is a way of representing that x lies within a particular set.</em>

6 0
3 years ago
What is y+2=-4(X-6) in Ax+By=C form
PSYCHO15rus [73]
Y+2=-4x+24
2=-4x-y+24
-22=-4x-y
7 0
3 years ago
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