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4 years ago

Given the points (-1,-5) and D(-7, 11). find the coordinates of point E

Mathematics

1 answer:

valkas [14]4 years ago

3 0

Answer:

The coordinates of point E are (-19/4,8)

Step-by-step explanation:

To find this, we use the internal division formula;

The formula is as follows;

(x ,y) = mx2 + nx1/(m + n) , my2 + ny1/(m + n)

From the question;

m = 5 n = 3

x1 = -1 , y1 = -5

x2 = -7 , y2 = 11

Substitute these values;

(x ,y) = 5(-7) + 3(-1)/(3 + 5) , 5(11) + 3(-5)/(5 + 3)

(x , y) = (-35-3)/8, (55-15)/8

(x,y ) = -38/8, 40/8

(x,y) = -19/4, 5

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2 years ago

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2 years ago

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I am Lyosha [343]

Option C

The ratio for the volumes of two similar cylinders is 8 : 27

<h3><u>Solution:</u></h3>

Let there are two cylinder of heights "h" and "H"

Also radius to be "r" and "R"

$\text { Volume of a cylinder }=\pi r^{2} h$

Where π = 3.14 , r is the radius and h is the height

Now the ratio of their heights and radii is 2:3 .i.e

$\frac{\mathrm{r}}{R}=\frac{\mathrm{h}}{H}=\frac{2}{3}$

<em><u>Ratio for the volumes of two cylinders</u></em>

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{\pi r^{2} h}{\pi R^{2} H}$

Cancelling the common terms, we get

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\left(\frac{\mathrm{r}}{R}\right)^{2} \times\left(\frac{\mathrm{h}}{\mathrm{H}}\right)$

Substituting we get,

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\left(\frac{2}{3}\right)^{2} \times\left(\frac{2}{3}\right)$

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{2 \times 2 \times 2}{3 \times 3 \times 3}$

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{8}{27}$

Hence, the ratio of volume of two cylinders is 8 : 27

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3 years ago