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3 years ago

For each value of w, determine wheather it is a soultion to -5 -6w ≤7

1 answer:

3 0

So find the solutions to w we need to get w alone

<_ and >_ would be the bigger and smaller and equal to since I don't know how to make that sign with my keyboard :)

-6w<_12

W>_-2

Meaning that the solutions of the equation would always work as long as it's equal to to bigger than -2 such as 0,1,3,100000 :)

You might be interested in

How do you factor 125-x^3?

xz_007 [3.2K]

Step-by-step explanation:

We have

$125 - x {}^{3}$

First, 125 is a perfect cube because

$5 \times 5 \times 5 = 125$

and

x^3 is a perfect cube because

$x \times x \times x = x {}^{3}$

so we can use the difference of cubes identity

$( {x}^{3} - {y}^{3} ) = (x - y)( {x}^{2} + xy + {y}^{2} )$

Let say we have two perfect cubes:

64 because 8×8×8=64

and 27 because 3×3×3=27 and let subtract

$64 - 27$

we know that

$64 - 27 = 37$

but using the difference of cubes identity we should get the same thing.

Remeber cube root of 64 is 4 and cube root of 27 is 3 so we have

$(4 - 3)( {4}^{2} + 4(3) + 3 {}^{2} )$

$1(16 + 12 + 9) = 1(37) = 37$

So the difference of cubes works for real numbers. This is a good way to help remeber the identity using real numbers.

Back on to the topic,

we know that 5 is cube root of 125 and x is the cube root of x^3 so we have

$(5 - x)( {5}^{2} + 5x + {x}^{2} ) =$

$(5 - x)(25 + 5x + {x}^{2} )$

3 0

2 years ago

Read 2 more answers

Simplify the expression. Show your work. 22 + (3^2 – 4^2)

irga5000 [103]

22 + (3^2 – 4^2)
= 22 + (9 – 16)
= 22 -7
= 15

6 0

3 years ago

How can i solve this? please help.

iogann1982 [59]

Answer:SEARCH NYO SA GOGGLE

Step-by-step explanation:PLZZ

6 0

2 years ago

]solomon needs to justify the formula for the arc length of a sector. which expression best completes this argument? the circumf

Anna35 [415]

Answer:

$\frac{2 \pi r}{\frac{360^{\circ}}{n^{\circ}}}$ best completes this argument

Step-by-step explanation:

Circumference of circle = $\pi \cdot d$

Where d is the diameter of circle

We are given that if equally sized central angles, each with a measure of n°, are drawn, the number of sectors that are formed will be equal to $\frac{360^{\circ}}{n^{\circ}}$