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Igoryamba
4 years ago
8

Evaluate the formula v=bh/3 for b = 36 in.2 and h = 11 in.

Mathematics
2 answers:
KonstantinChe [14]4 years ago
7 0

Step-by-step explanation:  The volume of the pyramid is defined by the formula <em>v = ( b·h ) / 3</em> , where <em>b</em> is the surface of the base of the pyramid, and <em>h</em> is the altitude of the pyramid. The multiplied values of the surface of the base and the altitude is divided by three, and the value obtained represents the volume of the pyramid. Since the values ​​of the base surface and the altitude are given, it is only necessary to insert the given values ​​in the formula:

<em>b = 36 in²</em>

<em>h = 11 in </em>

<em>v = ( 36 in²·11 in) / 3 = 132 in³</em>

<em></em>

From the given values ​​it can be seen that the surface of the base <em>b</em> is given in square inches, while the altitude value <em>h</em> is in inches, the result that represents the value of the volume is given in cubic inches.

Over [174]4 years ago
4 0
V=36times 11/3
v=132
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OverLord2011 [107]

There are two c's. You must pay attention to capitalization, there's a lowercase c and an uppercase C which represent two different variables. Also, the W is capitalized which could make your answer incorrect if you don't use the same notation.

Solving for small c..

C = \frac{Wtc}{1,000}   \\\\ 1,000C = Wtc \\\\\frac{1,000C}{Wt}= c

So it's the answer shown in the picture, but it  should be a capital W instead of a lowercase w.  






3 0
3 years ago
Perform the indicated operations. Write the answer in standard form, a+bi.<br> (8 - i)^2 + (8 + i)^2
ArbitrLikvidat [17]

Answer:

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3 years ago
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6 0
3 years ago
What is the solution to he equation (y/y-4)-(4/y+4)=3^2/y^2-16
kicyunya [14]

Answer:

y=\pm i \sqrt{7}

Step-by-step explanation:

Given equation is \frac{y}{\left(y-4\right)}-\frac{4}{\left(y+4\right)}=\frac{3^2}{(y^2-16)}

Factor denominators then solve by making denominators equal

\frac{y}{\left(y-4\right)}-\frac{4}{\left(y+4\right)}=\frac{3^2}{(y^2-16)}

\frac{y}{\left(y-4\right)}-\frac{4}{\left(y+4\right)}=\frac{9}{(y+4)\left(y-4\right)}

\frac{y\left(y+4\right)-4\left(y-4\right)}{\left(y-4\right)\left(y+4\right)}=\frac{9}{(y+4)\left(y-4\right)}

y\left(y+4\right)-4\left(y-4\right)=9

y^2+4y-4y+16=9

y^2=9-16

y^2=-7

take squar root of both sides

y=\pm \sqrt{-7}

y=\pm i \sqrt{7}

Hence final answer is y=\pm i \sqrt{7}.

7 0
3 years ago
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Dennis_Churaev [7]

Answer:

1. 14.666 ¯ over the 3

2. 14.034 ¯ over the 3

Step-by-step explanation:

5 0
3 years ago
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