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ikadub [295]
2 years ago
9

Find the following sums ( for letter C)

Mathematics
1 answer:
anygoal [31]2 years ago
6 0

Each number in the sum is even, so we can remove a factor of 2.

2 + 4 + 6 + 8 + ... + 78 + 80 = 2 (1 + 2 + 3 + 4 + ... + 39 + 40)

Use whatever technique you used in (a) and (b) to compute the sum

1 + 2 + 3 + 4 + ... + 39 + 40

With Gauss's method, for instance, we have

S = 1 + 2 + 3 + ... + 38 + 39 + 40

S = 40 + 39 + 38 + ... + 3 + 2 + 1

2S = (1 + 40) + (2 + 39) + ... + (39 + 2) + (40 + 1) = 40×41

S = 20×21 = 420

Then the sum you want is 2×420 = 840.

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PLEASE I REALLY NEED YOUR HELP!
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Answer:

x = 28

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Step-by-step explanation:

∠BAE ≅∠DAC because they are vertical angles

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f_X(x)=\begin{cases}0.1e^{-0.1x}&\text{for }x>0\\0&\text{otherwise}\end{cases}

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b. 8:15 and 8:30 AM are the 15 and 30 minute marks, respectively. The probability of arriving at some point between them is

\displaystyle\int_{15}^{30}f_X(x)\,\mathrm dx\approx0.173

c. The probability of arriving on any given day before 8:40 AM (the 40 minute mark) is

\displaystyle\int_0^{40}f_X(x)\,\mathrm dx\approx0.982

The probability of doing so for at least 2 of 5 days is

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d. Integrate the PDF to obtain the CDF:

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F_X(30)-F_X(15)\approx0.950-0.777=0.173

7 0
3 years ago
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D.4900
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3 years ago
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∆ABC is isosceles. If m∠B = 35° what is the measure of ∠C?
Damm [24]

Answer:

If ABC is isosceles, then <C is 35, and <A should be 110.

Step-by-step explanation:

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