Hannah has 350 marbles, she gave 50 to each student, how many students are there?
2 answers:
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Answer:
1) B. The differences are normally distributed or the sample size is large
C. The sample size mus be large
E. The sampling method results in an independent sample
2) The null hypothesis H₀: =
The alternative hypothesis Hₐ: <
Test statistic, t = -0.00693
p- value = 0.498
Do not reject Upper H₀ because, the P-value is greater than the level of significance. There is sufficient evidence to conclude that sons are the same height as their fathers at 0.10 level of significance
Step-by-step explanation:
1) B. The differences are normally distributed or the sample size is large
C. The sample size mus be large
E. The sampling method results in an independent sample
2) The null hypothesis H₀: =
The alternative hypothesis Hₐ: <
The test statistic for t test is;
The mean
Height of Father, h₁, Height of Son h₂
72.4, 77.5
70.6, 74.1
73.1, 75.6
69.9, 71.7
69.4, 70.5
69.4, 69.9
68.1, 68.2
68.9, 68.2
70.5, 69.3
69.4, 67.7
69.5, 67
67.2, 63.7
70.4, 65.5
= 69.6
s₁ = 1.58
= 69.9
s₂ = 3.97
n₁ = 13
n₂ = 13
(We reversed the values in the square root of the denominator therefore, the sign reversal)
t = -0.00693
p- value = 0.498 by graphing calculator function
P-value > α Therefore, we do not reject the null hypothesis
Do not reject Upper H₀ because, the P-value is greater than the level of significance. There is sufficient evidence to conclude that sons are the same height as their fathers at 0.10 lvel of significance
Answer:
C) At most one sample is mutated
Step-by-step explanation:
If there are 15 samples, it means that 15 is the total (100%) of samples. Then, if we know that there is a chance that 3% are mutated, then we calculate the 3% of 15:
This means that at most one sample is mutated, as this result is not zero (we discard answer A), and 0.45 is not more than half of the samples.