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2 years ago

How do I solve these? Please give an explanation!!

Mathematics

1 answer:

serious [3.7K]2 years ago

7 0

Answer:

Meron sagot yan ting na mosa snap solve

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What is the slope of the line represented by the points in the table?

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Answer: D

Step-by-step explanation: I just took the quiz, it should work

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2 years ago

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15 pts!

shusha [124]

Answer:

They will have 53 CDs when they have the same amount. You have to add the amounts 5 times

Step-by-step explanation:

8+9=17+9=26+9=35+9=44+9=53

18+7=25+7=32+7=39+7=46+7=53

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3 years ago

Convert 8.25% to a decimal

Kisachek [45]

Answer: 0.0825

Step-by-step explanation:

8.25% to decimal is simply divide 8.25 by 100

8.25/100= 0.0825

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2 years ago

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Which is the value of the expression (StartFraction (10 Superscript 4 Baseline) (5 squared) Over (10 cubed) (5 cubed)) cubed?

Flura [38]

Answer:

The value to the given expression is 8

Therefore $\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3=8$

Step-by-step explanation:

Given expression is (StartFraction (10 Superscript 4 Baseline) (5 squared) Over (10 cubed) (5 cubed)) cubed

Given expression can be written as below

$\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3$

To find the value of the given expression:

$\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3=\frac{((10^4)(5^2))^3}{((10^3)(5^3))^3}$

( By using the property ( $(\frac{a}{b})^m=\frac{a^m}{b^m}$ )

$=\frac{(10^4)^3(5^2)^3}{(10^3)^3(5^3)^3}$

( By using the property $(ab)^m=a^mb^m$ )

$=\frac{(10^{12})(5^6)}{(10^9)(5^9)}$

( By using the property $(a^m)^n=a^{mn}$ )

$=(10^{12})(5^6)(10^{-9})(5^{-9})$

( By using the property $\frac{1}{a^m}=a^{-m}$ )

$=(10^{12-9})(5^{6-9})$ (By using the property $a^m.b^n=a^{m+n}$ )

$=(10^3)(5^{-3})$

$=\frac{10^3}{5^3}$ ( By using the property $a^{-m}=\frac{1}{a^m}$ )

$=\frac{1000}{125}$

$=8$

Therefore $\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3=8$

Therefore the value to the given expression is 8

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3 years ago

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Which of the following are like radicals? Check all of the boxes that apply

ElenaW [278]

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2 years ago