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4 years ago

10

Please answer pronto!!!! Marc thinks the only time a ploynomial in the form of ax^2 + bc + c cannot be factored is when at least

one of the values for a, b, or c is a prime number. Find a counterexample for Marc's statement.

1 answer:

satela [25.4K]4 years ago

8 0

Good luck okkkkkk this is hard super

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e. Translate the word problem below into an equation; then solve. It only takes Vera 2 hours to sew 1 dress, but it takes Ivy 4

Daniel [21]

Using the together rate, it is found that it would take them 16 hours to sew 12 dresses.

<h3>What is the together rate?</h3>

The together rate is the <u>sum of each separate rate</u>.

In this problem, we have that:

Vera's rate is of 1/2.

Ivy's rate is of 1/4.

Hence, the together rate is the time it would take them to produce one dress working together, and is given by:

$\frac{1}{x} = \frac{1}{2} + \frac{1}{4}$

$\frac{1}{x} = \frac{2 + 1}{4}$

$3x = 4$

$x = \frac{4}{3}$

Then one dress takes $\frac{4}{3}$ of an hour, and the time for twelve dresses is:

$t = 12 \times \frac{4}{3} = 4(4) = 16$

It would take them 16 hours to sew 12 dresses.

To learn more about the together rate, you can take a look at brainly.com/question/25159431

6 0

2 years ago

3n + 9 = 27<br><br> n = ?<br><br> solve for n

Debora [2.8K]

Answer:

6

Step-by-step explanation:

7 0

3 years ago

PLEASE HURRY!!!!!!

Anni [7]

Answer:

Step-by-step explanation:

The manager visits a park and interviews people who are waiting to use the tennis courts.

7 0

4 years ago

Please help me I will give a brainly!!!!

nydimaria [60]

Answer:

Yes

Step-by-step explanation:

1 : The athlete's hands push the medicine ball forward. The medicine ball pushes the athlete's hands backward.

2: Friction

3: The first pair of action-reaction force pairs is: foot A pushes ball B to the right; and ball B pushes foot A to the left. The second pair of action-reaction force pairs is: foot C pushes ball B to the left; and ball B pushes foot C to the right

7 0

2 years ago

2 Here are two equations:

MatroZZZ [7]

a. (3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. No, it is not possible to have more than one (x,y) pair that is solution to both equations

Step-by-step explanation:

a. Decide whether each neither of the equations,

i (3,4)

ii. (4,2.5)

ill. (5,5)

iv. (3,2)

To decide whether each point is solution to equations or not we will put the point in the equations

Equations are:

Equation 1: 6x + 4y = 34

Equation 2: 5x – 2y = 15

<u>i (3,4) </u>

Putting in Equation 1:

$6(3) + 4(4) = 34\\18+16=34\\34=34\\$

Putting in Equation 2:

$5(3) - 2(4) = 15\\15-8 = 15\\7\neq 15$

<u>ii. (4,2.5)</u>

Putting in Equation 1:

$6(4) + 4(2.5) = 34\\24+10=34\\34=34\\$

Putting in Equation 2:

$5(4) - 2(2.5) = 15\\20-5 = 15\\15=15$

<u>ill. (5,5)</u>

$6(5) + 4(5) = 34\\30+20=34\\50\neq 34$

Putting in Equation 2:

$5(5) - 2(5) = 15\\25-10 = 15\\15=15$

<u>iv. (3,2)</u>

$6(3) + 4(2) = 34\\18+8=34\\26\neq 34$

Putting in Equation 2:

$5(3) - 2(2) = 15\\15-4 = 15\\11\neq 15$

Hence,

(3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. Is it possible to have more than one (x, y) pair that is a solution to both

equations?

The simultaneous linear equations' solution is the point on which the lines intersect. Two lines can intersect only on one point. So a linear system cannot have more than one point as a solution

So,

a. (3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. No, it is not possible to have more than one (x,y) pair that is solution to both equations

Keywords: Linear equations, Ordered pairs

Learn more about linear equations at:

#LearnwithBrainly

8 0

3 years ago