Answer:
20 months
Step-by-step explanation:
Initial difference = 500$
Monthly difference = 25$
500 / 25 = 20
Answer:
Null Hypothesis: H_0: \mu_A =\mu _B or \mu_A -\mu _B=0
Alternate Hypothesis: H_1: \mu_A >\mu _B or \mu_A -\mu _B>0
Here to test Fertilizer A height is greater than Fertilizer B
Two Sample T Test:
t=\frac{X_1-X_2}{\sqrt{S_p^2(1/n_1+1/n_2)}}
Where S_p^2=\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2}
S_p^2=\frac{(14)0.25^2+(12)0.2^2}{15+13-2}= 0.0521154
t=\frac{12.92-12.63}{\sqrt{0.0521154(1/15+1/13)}}= 3.3524
P value for Test Statistic of P(3.3524,26) = 0.0012
df = n1+n2-2 = 26
Critical value of P : t_{0.025,26}=2.05553
We can conclude that Test statistic is significant. Sufficient evidence to prove that we can Reject Null hypothesis and can say Fertilizer A is greater than Fertilizer B.
Since they are similar, that means they are proportionally the same.
So KL is similar to PN
JL is similar to PM
So,
You need to find how much bigger is the second triangle from first.
It is proportionally scaled up.
KL/JL = PN/ PM
You basically put in order of triangles. Left triangle on left side of equal sign and right triangle on right side of equal sign. You put in denominator the similar sides and numerator the similar sides (the side that is similar to the side of the other triangle)
5/6 = PN / 9
Cross-multiply
PN * 6 = 5*9
6PN = 45
PN =45/6
PN =7.5
Answer:
43.98
Step By Step Explanation: