What is the surface area of a prism that has 4in, 4in and 2in sides

a square red rug has a purple square in the center. the side length of the purple square is x inches. the width of the red band

Bumek [7]

Answer:

Area of red band is $(20x + 100) inch^{2}$

Step-by-step explanation:

We know that area of square = $side^{2}$

Please refer to the attached figure, we have to calculate the area of red band.

Required area = Area of square ABCD - Area of purple square

Side of purple square = $x$

So, area of purple square = $x^{2}$

ABCD is a square with purple square at the center and there is symmetry in the figure.

So, width of red band towards both the end is 5 inches.

$\Rightarrow \text{side of }ABCD = 5 + 5 +x = (x+10) inches$

Required area = $(x+10)^{2} - x^{2}$

Using formula $a^{2} - b^{2} = (a-b)\times (a+b)$

$\Rightarrow (x+10-x)(x+10+x)\\\Rightarrow (10)(2x+10)\\\Rightarrow (20x+100)$

Hence, Area of red band is $(20x + 100) inch^{2}$

5 0

3 years ago

Brian just started using a budget. He proudly tells friends that his budget helps him know where his money is being spent. It al

belka [17]

Answer: Brian has some understanding of budgeting. However, a budget does not create more money each month. It just helps him use his money better.

This is what Brian said and my assessment:


.... his budget helps him know where his money is being spent TRUE

It allows him to spend some money on entertainment with the peace of mind that he will be able to pay the rent: TRUE

...and even gives him more money each month NOT REALLY ... money is not created by the budget

3 0

3 years ago

Which fraction is equivalent to this decimal? 0.16¯

rewona [7]

Answer: 4/25 ILY <3

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Solve for c: 2/8x - 4 = -10

Kamila [148]

2/8x - 4 = -10
+ 4 + 4
(8/2)2/8x = -6 (8/2)
x = -48/2
x = -24

4 0

3 years ago

The Skittles jar has a radius of 3.5 cm and a height of 11.5 cm. Using the two given boxes for reference what would be a good es

nevsk [136]

Answer:

1052

Step-by-step explanation:

The two given boxes for reference are presented below.

Since we know the dimensions of the first container, we can calculate its volume.

$V_1= 5 \text{cm} \cdot 4 \text{cm} \cdot 4 \text{cm} = 80 \text{cm}^3$

The first container held 192 skittles. Using that fact, now that we know the volume of the first box, we can calculate the volume of a single skittle.

$v = \frac{80}{192} = 0.416 \approx 0.42 \text{cm}^3$

The second container held 258 skittles.

The volume of the second box is:

$V_2 = 12 \text{cm}\cdot 3 \text{cm} \cdot 3 \text{cm} = 108 \text{cm}^3$

Using this facts, the volume of a single skittle would be

$v = \frac{108}{258} = 0.418 \approx 0.42 \text{cm}^3$

Therefore, the volume of single skittle is around to 0.42 cm³.

A skittle jar is a cylinder. Its volume is calculated by the formula

$V = r^2h \pi$ ,

where $r$ is the radius and $h$ is the height. From the given data, we have $r = 3.15 \text{cm}$ and $h = 11.5 \text{cm}$ . Hence, the volume of the jar is

$V = 3.5^2 \cdot 11.5 \cdot 3.14 = 442 \text{cm}^3$

Now, we can determine the number of skittles in the jar. Let $n$ be the number of skittles in the jar. Then,

$n = \frac{\text{volume of the jar}}{\text{volume of a skittle}} = \frac{V}{v} = \frac{442}{0.42} = 1052.38 \approx 1052\\$

4 0

3 years ago