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Stells [14]
2 years ago
9

In order for a ladder to reach a height of 10 feet, it needs to be placed at a 75° angle to the ground. The ground already has a

n elevation of 15°. What degree does the ladder need to be set at?
Mathematics
1 answer:
Dmitry [639]2 years ago
4 0

Since the ground already has an elevation of 15 degrees, the ladder needs to

be set at 60 degrees to reach a height of 10 ft.

In order for a ladder to reach a height of 10 feet, the ladder needs to be

placed at 75 degrees angle to the ground. This is when the ground has no

angle of elevation or when it flat.

Now, if the ground has an angle of elevation of 15 degrees , the degrees in

angle the ladder needs to be set can be solved as follows:

<h3>Angles in degree: </h3>
  • 75  - 15 = 60 degrees

Therefore, the ladder needs to set at an angle of 60 degrees if the

elevation of the ground is already 15 degree. The elevation of the ground

will complement the angle in degrees required for the ladder to reach 10

feet.

learn more on elevation: brainly.com/question/9195919?referrer=searchResults

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The length of a rectangle is 5 inches more than the width. The area is 33 square inches. Find the length and width . Round to th
EleoNora [17]

Answer:

the length and width . Round to the nearest tenth are 8.8 inches and 3.8 inches respectively.

Step-by-step explanation:

The area A of a rectangle is the product of the length L and width W. This may be expressed mathematically as

A = L * W

As such, given that the length is 5 inches more than the width,

L = W + 5

33 = W(W + 5)

W² + 5W  - 33 = 0

Using the formula method which states that

s = -b±√(b²-4ac)/2a

W = -5 ± √5² - 4(1)(-33)/2

= -5 ± 12.53/2

= 7.53/2 (since length cannot be negative)

= 3.755 inches

L = 3.755 + 5

= 8.755 inches

6 0
3 years ago
The data represents the number of hours 10 students slept on sunday night (6,6,7,7,7,8,8,8,8,9) are there any outliers?
olga nikolaevna [1]

It's still remained un-touched. But will it hold for long?

3 0
3 years ago
Please help! <br> 70+23x-5+110+14x=360 (please show step bc I need to turn in work-paper) Thank you!
daser333 [38]

x = 5

<u>explanation</u>

70 + 23x - 5 + 110 + 14x = 360

first you group the like terms

23x + 14x + 70 - 5 + 110 = 360

then combine the like terms

<u>23x + 14x</u>    <u>70 - 5 + 110</u>

37x + 175 = 360

subtract 175 from both sides

175 - 175 = 0     360 - 175 = 185

to get

37x = 185

divide both sides by 37

37x/37 = 0     185/37= 5

which gives you

x = 5

3 0
3 years ago
A turtle swims at a speed of 1584 meters per hour. A girl swims at a speed of 1380 millimeters per second. 10 mm = 1 cm 1 m = 10
adelina 88 [10]
The girl's speed is 1380mm/sec * 1cm/10mm * 60sec/minute (since 1cm=10mm and 60 sec=1 minute)= 1380*60cm/10min= 1380*6cm/min
=8280 cm/min. For the turtle, we have 1584 m/hr * 1 hr / 60 min * 100 cm /1m (we have to make sure that they cross out, so e.g. for the hour we multiply it by 1 hr/60 min since the original hour is on the bottom)= 158,400cm/60min
=15840cm/6min
= 2640 cm/min
Since the girl is 8280 cm/min and the turtle is 2640 cm/min, we divide them to get 8280/2640= around 3.136 cm/min

3 0
3 years ago
Read 2 more answers
For the point P(2,-14) and Q(9,-9) find the distance d(P,Q) and the coordinates of the midpoint M of the segment PQ
marin [14]

Answer:

Step-by-step explanation:

Distance : \sqrt{(x2-x1)^2 + (y2 - y1)^2} = \sqrt{(9-2)^2 + (-9+14)^2}= \sqrt{49 + 25} = \sqrt{74}

Midpoint :

x (m) = (2+9)/2 = 11/2

y (m) = (-14-9)/2 = -23/2

M (11/2, -23/2)

5 0
3 years ago
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