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2 years ago

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The point (5,-12) lies on the terminal side of an angel theta in standard position. Find the exact value of cot theta. Express t

he answer as a fraction reduced to the lowest term

1 answer:

saw5 [17]2 years ago

8 0

Answer:

$cot\theta=-\frac{5}{12}$

Step-by-step explanation:

We are given that the point (5,-12) lies on the terminal side of an angle theta in standard position.

We have to find the exact value of $cot\theta$ .

Let

Point (x,y)=(5,-12)

$r=\sqrt{x^2+y^2}$

Substitute the values

$r=\sqrt{5^2+(-12)^2}$

$r=\sqrt{169}=13$

We know that

$cot\theta=\frac{x}{y}$

Using values

$cot\theta=-\frac{5}{12}$

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