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iogann1982 [59]
3 years ago
15

-2x+7y=14 identify the x-intercept and y-intercept

Mathematics
2 answers:
laiz [17]3 years ago
8 0
-2x=14-7y
X=(14-7y)/-2

7y=14+2x
Y=(14+2x)/7
Juli2301 [7.4K]3 years ago
8 0

Answer:

x=7/2y − 7

Step-by-step explanation:

Let's solve for x.

−2x+7y=14

Step 1: Add -7y to both sides.

−2x+7y+−7y=14+−7y

−2x=−7y+14

Step 2: Divide both sides by -2.

−2x/−2 = −7y+14/−2

x=7/2y − 7

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What is X-5+10x+3???
Alekssandra [29.7K]

Answer:

-2+11x

Step-by-step explanation:

Combine like terms

(-5+3)+(x+10x)

-5+3 = -2

x+10x = 11x

-2+11x

8 0
3 years ago
Complete the identity.<br> 1) sec^4 x + sec^2 x tan^2 x - 2 tan^4 x = ?
Alecsey [184]

Answer:

See Explanation

Step-by-step explanation:

<em>Question like this are better answered if there are list of options; However, I'll simplify as far as the expression can be simplified</em>

Given

sec^4 x + sec^2 x tan^2 x - 2 tan^4 x

Required

Simplify

(sec^2 x)^2 + sec^2 x tan^2 x - 2 (tan^2 x)^2

Represent sec^2x with a

Represent tan^2x with b

The expression becomes

a^2 + ab- 2 b^2

Factorize

a^2 + 2ab -ab- 2 b^2

a(a + 2b) -b(a+ 2 b)

(a -b) (a+ 2 b)

Recall that

a = sec^2x

b = tan^2x

The expression (a -b) (a+ 2 b) becomes

(sec^2x -tan^2x) (sec^2x+ 2 tan^2x)

..............................................................................................................................

In trigonometry

sec^2x =1  +tan^2x

Subtract tan^2x from both sides

sec^2x - tan^2x =1  +tan^2x - tan^2x

sec^2x - tan^2x =1

..............................................................................................................................

Substitute 1 for sec^2x - tan^2x in (sec^2x -tan^2x) (sec^2x+ 2 tan^2x)

(1) (sec^2x+ 2 tan^2x)

Open Bracket

sec^2x+ 2 tan^2x ------------------This is an equivalence

(secx)^2+ 2 (tanx)^2

Solving further;

................................................................................................................................

In trigonometry

secx = \frac{1}{cosx}

tanx = \frac{sinx}{cosx}

Substitute the expressions for secx and tanx

................................................................................................................................

(secx)^2+ 2 (tanx)^2 becomes

(\frac{1}{cosx})^2+ 2 (\frac{sinx}{cosx})^2

Open bracket

\frac{1}{cos^2x}+ 2 (\frac{sin^2x}{cos^2x})

\frac{1}{cos^2x}+ \frac{2sin^2x}{cos^2x}

Add Fraction

\frac{1 + 2sin^2x}{cos^2x} ------------------------ This is another equivalence

................................................................................................................................

In trigonometry

sin^2x + cos^2x= 1

Make sin^2x the subject of formula

sin^2x= 1  - cos^2x

................................................................................................................................

Substitute the expressions for 1  - cos^2x for sin^2x

\frac{1 + 2(1  - cos^2x)}{cos^2x}

Open bracket

\frac{1 + 2  - 2cos^2x}{cos^2x}

\frac{3  - 2cos^2x}{cos^2x} ---------------------- This is another equivalence

8 0
3 years ago
What is the value of the underlined digit in 91,764,350?​
VMariaS [17]

Digit wise values.

\\ \sf\longmapsto 9=90000000

\\ \sf\longmapsto 1=1000000

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\\ \sf\longmapsto 6=60000

\\ \sf\longmapsto 4=4000

\\ \sf\longmapsto 3=300

\\ \sf\longmapsto 5=50

\\ \sf\longmapsto 0=0

8 0
3 years ago
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Ummm eeee i dont knowwwe
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I believe 2 2/3 quarts of the mixture. Cheers!
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