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3 years ago

A number n is increased by 8. If the cube root of that results equals -0.5, what is the value of n?

Mathematics

1 answer:

jek_recluse [69]3 years ago

8 0

The cube root of (n increased by 8), or ∛(n+8), is -0.5, or -1/2.

∛(n+8) = -1/2. To solve this for n, cube both sides, obtaining n+8 = -1/8.

Eliminate the fraction by mult. all three terms by 8: 8n + 64 = -1

Solving for n: 8n = -65, so that n = -65/8.

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Answer: Our required probability would be 0.9641.

Step-by-step explanation:

Since we have given that

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So, Number of minutes he worked in a day = $8\times 60=480\ minutes$

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Using the normal distribution, we get that

$z=\dfrac{\bar{x}-\mu}{s}\\\\z=\dfrac{2.18-2.0}{0.10}\\\\z=1.8$

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3 years ago

Please help to find an explicit formula for calculating the sum Mn

defon

The explicit formula for calculating the sum is

$S_N=\frac{n(n-1)}{2} \cdot\frac{n(n+1)}{2}$

The sum of the nth term of a sequence is expressed as;

$S_n=\frac{n}{2}(2a+(n-1)d)$

a is the first term

d is the common difference

n is the number of terms

For the sequence 0 + 1 + 2 + 3 +...

$S_n=\frac{n}{2}(2(0)+(n-1)1)\\S_n= \frac{n}{2}(n-1)\\S_n= \frac{n(n-1)}{2}$

Similarly for the sequence:

1 + 2+ 3 + 4+...

$S_n=\frac{n}{2}(2(1)+(n-1)1)\\S_n= \frac{n}{2}(2+n-1)\\S_n= \frac{n(n+1)}{2}$

Taking the product of the sum to get the explicit formula for calculating the sum

$S_N=\frac{n(n-1)}{2} \cdot\frac{n(n+1)}{2}$

Learn more here: brainly.com/question/24547297

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Step-by-step explanation:

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3 years ago

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Step-by-step explanation:

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3 years ago

Write the statement for the problem in mathematical language. Use x for the tens digit and y for the unit digits in the two digi

Nutka1998 [239]

Answer:

Step-by-step explanation:

A two-digit number (xy) will have the value 10x+y. The sum of its digits is x+y.

You want ...

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<em>Check</em>

Its sum of digits is 1+8 = 9. 2×9 = 18.

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<em>Comment on the relationship in the problem</em>

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3 years ago