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Sever21 [200]
3 years ago
6

A number n is increased by 8. If the cube root of that results equals -0.5, what is the value of n?

Mathematics
1 answer:
jek_recluse [69]3 years ago
8 0

The cube root of (n increased by 8), or  ∛(n+8), is -0.5, or -1/2.

∛(n+8) = -1/2.  To solve this for n, cube both sides, obtaining n+8 = -1/8.

Eliminate the fraction by mult. all three terms by 8:             8n + 64 = -1

Solving for n:  8n = -65, so that n = -65/8.

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PLZZZZZZZZZZZZZZZZ HELP
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Answer:

The first box in the girl row is 18, the second one in the boy row is 8, and the bottom one is also 18.

Step-by-step explanation:

To get 81 to 9, you have to divide by 9, which means you have to do the same to 72. You get the ration 9 to 8, 9 being girls and 8 being guys. Then to get from 8 guys to 16, you have to multiply by 2, which means you do the same to 9 and get the answer of 18 girls. Hope this helps :)

5 0
3 years ago
The solution set of the equation 8x + 12 = 5x – 21.
erastovalidia [21]

Answer:

8x + 12 = 5x -21

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Hope it helps

6 0
3 years ago
Find the 4th term (x-y)^12
maria [59]

Answer:

The fourth term of the expansion is -220 * x^9 * y^3

Step-by-step explanation:

Question:

Find the fourth term in (x-y)^12

Solution:

Notation: "n choose k", or combination of k objects from n objects,

C(n,k) = n! / ( k! (n-k)! )

For example, C(12,4) = 12! / (4! 8!) = 495

Using the binomial expansion formula

(a+b)^n

= C(n,0)a^n + C(n,1)a^(n-1)b + C(n,2)a^(n-2)b^2 + C(n,3)a^(n-3)b^3 + C(n,4)a^(n-4)b^4 +....+C(n,n)b^n

For (x-y)^12, n=12, k=3, a=x, b=-y, and the fourth term is

C(n,3)a^(n-3)b^3

=C(12,3) * x^(12-3) * (-y)^(3)

= 220*x^9*(-y)^3

= -220 * x^9 * y^3

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3 years ago
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Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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6 0
3 years ago
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