Question

Mrs. Meyers is growing vines along the sides of her house. On the west side the vines are 2 4/10 meters tall. On the east side the vines are 5 8/10 meters taller than the ones on the west side. How tall are the vines on the east side?

Answer 1

E=east vine’s height

e=24/10+58/10
e=82/10

e=8 1/5

Answer 2

Height of the vines on the west side

$=2\frac{4}{10}$

But

$=\frac{4}{10}=\frac{2}{5}$

So length of vines in the west

= $=2\frac{2}{5}$

Height of vines on the west side as an improper fraction

= $\frac{12}{5}$

Now Vines on the east are

$5\frac{8}{10}=5\frac{4}{5}$

taller

In the mixed fraction it is

$\frac{29}{5}$

So height of vines

$=\frac{29}{5}+\frac{12}{5}$

$=\frac{41}{5}$

$=8\frac{1}{5}$

So the vines on the east are $8\frac{1}{5} m$