23) x^2 * 8
24) x^3 - 15
25) (x/4) + 5
26) 4 less than the product of 8 and a number is 16
27) The sum of a number and 3 divided by 4 is 5
28) 3 less than 4 times a number squared is 13
To find the gradient of the perpendicular line, we know that we must do the negative inverse of the current line's gradient
-6x from the old line will now be 1/6x
we are given points on that line and we therefore use the points and the new gradient to find the equation of the line using this formula
y-y1=m(x-x1) where m is the gradient
input the values that we have
y-5=1/6(x--4)
rearrange
y-5=1/6(x+4)
y-5=1/6x+4/6
6y-30=x+4
6y=x+34
y=1/6x+34/6
y=1/6x+17/3
Answer:
The first one is F' each one is around $36
3x+3-x+(-7)>6
combine like terms on left side
2x-4>6
add 4 to both sides 2x>10
x=10/2 = 5
x>5
