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Katen [24]
3 years ago
8

Write the slope-intercept form of the equation of the line through the given point with the given slope.

Mathematics
1 answer:
SIZIF [17.4K]3 years ago
5 0
Slope itnercept is y=mx+b

ok, let's start with point slope form
y-y1=m(x-x1)
a point on the line is (x1,y1) and the slope is m
so given point (-3,4) and slope -3/4
y-4=-3/4(x-(-3))
y-4=-3/4(x+3)
distribute to solve for y
y-4=(-3/4)x-9/4
add 4 to both sides
y=(-3/4)x-9/4+4
y=(-3/4)x-9/4+16/4
y=(-3/4)x+7/4
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Step-by-step explanation:

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3 0
3 years ago
Mathwiz wya?? pic below i need help asap
n200080 [17]

Answer:

Step-by-step explanation:

First, you gotta work out the hypotenuse of ABC, which is AC.

To do that, you need to figure out the scale factor between the two right-angled triangles. You can do that for this question because this is a similar shapes question.

12.5/5 = 2.5

The scale factor length between the two triangles is 2.5.

You can use 2.5 now to work out AC, so AC would be 13 x 2.5, which gives 32.5.

Now that you've got the hypotenuse and BC of ABC, you can use Pythagoras's theorem to work out the length of AB

Pythagoras's theorem = a^2 + b^2 = c^2

a = BC = 12.5

b = AB = we need to work this out

c = AC (the hypotenuse we just worked out) = 32.5

12.5^2 + b^2 = 32.5^2 Let's both simplify and rearrange this at the same time so that we have our b on one side.

b^{2} = 1056.25 - 156.25

b = \sqrt{(1056.25 - 156.25)}

b = \sqrt{900}

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Perimeter of ABC = AB + BC + AC

= 30 + 12.5 + 32.5

= 75  Here's the perimeter for ABC.

8 0
2 years ago
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