Answer:
25
Step-by-step explanation:
30-60-90 Triangles
short leg = x
long leg = x
hypotenuse = 2x
A stuntman jumping off a 20-m-high building is modeled by the equation h = 20 – 5t2, where t is the time in seconds. A high-speed camera is ready to film him between 15 m and 10 m above the ground. For which interval of time should the camera film him?
Answer:

Step-by-step explanation:
Given:
A stuntman jumping off a 20-m-high building is modeled by the equation
-----------(1)
A high-speed camera is ready to making film between 15 m and 10 m above the ground
when the stuntman is 15m above the ground.
height
Put height value in equation 1





We know that the time is always positive, therefore 
when the stuntman is 10m above the ground.
height
Put height value in equation 1







Therefore ,time interval of camera film him is 
Answer:
B. $1,400
Step-by-step explanation:
8.75 x 20 x 8 =
8.75 x 160 = $1400
B
Hope that helps!
Answer:
The southwest corner of the garden will be 2 feet south and 3 feet west of the tree. A circle has a center at (3,5). What is the area of the circle to the nearest tenth of a square unit? Which of the following could be the vertices of the triangle? A garden that is 5 feet by 6 feet has a walkway that is 2 feet wide around it.
Area of the figure = 806.5 in²
Solution:
Length of the rectangle = 16 in
Breadth of the rectangle = 9 in
Area of the rectangle = length × breadth
= 16 × 9
Area of the rectangle = 144 in²
Base of the triangle = 31 in
Height of the triangle = 20 in
Area of the triangle = 

Area of the triangle = 310 in²
Parallel sides of the trapezium = 16 in and 31 in
Height of the trapezium = 35 – 20 = 15 in
Area of the trapezium = 


Area of the trapezium = 352.5 in²
Area of the figure = Area of rectangle + Area of triangle + Area of trapezium
= 144 in² + 310 in² + 352.5 in²
Area of the figure = 806.5 in²