Question

What two values of x are roots of the polynomial below

Answer 1

Both A and B will be answers to the solution. 

Since you already have the equation set and equal to 0, you can find the roots by first getting your a, b, and c values for the quadratic equation. 

a = 1 (number attached to the x^2)
b = -3 (number attached to the x)
c = 5 (number not attached to a variable)

Then we can use these values in the quadratic equation. 

$\frac{-b +/- \sqrt{ b^{2} -4ac } }{2a}$

$\frac{3 +/- \sqrt{ -3^{2} -4(1)(5) } }{2(1)}$

$\frac{3 +/- \sqrt{-11 } }{2}$