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Simora [160]
3 years ago
15

Cecil Green sells golf hats. He knows that most people will not pay more than $20 for a golf hat. Cecil needs a 40% markup on co

st. What should Cecil pay for his golf hats? (Round your answer to the nearest cent.) Cecil pays $
Mathematics
1 answer:
ahrayia [7]3 years ago
6 0
If we call the cost C then Cecil has to mark the product up 40% of C. That means he needs to charge the whole cost (100%) + 40% of the cost.

That is 140% of C. This amount needs to be $20.

In an equation we have 140% of C which can be written ( \frac{140}{100} )C set equal to $20. We solve for C which is the cost or what Cecil should pay for a hat.

(\frac{140}{100} )C=20
(\frac{7C}{5} )= \frac{20}{1}

This is a proportion so we cross-multiply to solve:
100=7c
\frac{100}{7} =C
C=$14.29
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The distinct factors of 75 are 1, 3, 5, 15, 25, 75.

Step-by-step explanation:

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Which method will NOT get you to the point (5,2.5)?
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Which statement describes the inverse of m(x) = x^2 – 17x?
DochEvi [55]

Given:

The function is

m(x)=x^2-17x

To find:

The inverse of the given function.

Solution:

We have,

m(x)=x^2-17x

Substitute m(x)=y.

y=x^2-17x

Interchange x and y.

x=y^2-17y

Add square of half of coefficient of y , i.e., \left(\dfrac{-17}{2}\right)^2 on both sides,

x+\left(\dfrac{-17}{2}\right)^2=y^2-17y+\left(\dfrac{-17}{2}\right)^2

x+\left(\dfrac{17}{2}\right)^2=y^2-17y+\left(\dfrac{17}{2}\right)^2

x+\left(\dfrac{17}{2}\right)^2=\left(y-\dfrac{17}{2}\right)^2        [\because (a-b)^2=a^2-2ab+b^2]

Taking square root on both sides.

\sqrt{x+\left(\dfrac{17}{2}\right)^2}=y-\dfrac{17}{2}

Add \dfrac{17}{2} on both sides.

\sqrt{x+\left(\dfrac{17}{2}\right)^2}+\dfrac{17}{2}=y

Substitute y=m^{-1}(x).

m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}

We know that, negative term inside the root is not real number. So,

x+\left(\dfrac{17}{2}\right)^2\geq 0

x\geq -\left(\dfrac{17}{2}\right)^2

Therefore, the restricted domain is x\geq -\left(\dfrac{17}{2}\right)^2 and the inverse function is m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}.

Hence, option D is correct.

Note: In all the options square of \dfrac{17}{2} is missing in restricted domain.

7 0
3 years ago
jamal completed his math homework in 2/3 of an hour and his reading homework in 3/5 of an hour. How much time did it take him to
Assoli18 [71]

Answer:

Step-by-step explanation: We have to add how much time it took him to do all of his homework. To do this, we have to add 2/3 and 3/5.

First, we have to find a LCM between 3 and 5.

The LCM between those numbers are 15.

Next we find out what number to multiply 3 by to get 15, we multiply it by 5.

2 * 5 = 10

3 * 5 = 15

Next we find out what number to multiply 5 by to get 15, we multiply it by 3.

3 * 3 = 9

5 * 3 = 15

10/15+9/15=19/15

We are left off with 1 4/15

So it took him 1 hour and 4/15 minutes to do his homework.

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How to do it ? plz answer it..​
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I hope you understand....

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