Yes is in first place because the quotient is 47
Answer:
it just is..
Step-by-step explanation:
Answer:
(3 square root of 2 , 135°), (-3 square root of 2 , 315°)
Step-by-step explanation:
Hello!
We need to determine two pairs of polar coordinates for the point (3, -3) with 0°≤ θ < 360°.
We know that the polar coordinate system is a two-dimensional coordinate. The two dimensions are:
- The radial coordinate which is often denoted by r.
- The angular coordinate by θ.
So we need to find r and θ. So we know that:
(1)
x = rcos(θ) (2)
x = rsin(θ) (3)
From the statement we know that (x, y) = (3, -3).
Using the equation (1) we find that:

Using the equations (2) and (3) we find that:
3 = rcos(θ)
-3 = rsin(θ)
Solving the system of equations:
θ= -45
Then:
r = 3\sqrt{2}[/tex]
θ= -45 or 315
Notice that there are two feasible angles, they both have a tangent of -1. The X will take the positive value, and Y the negative one.
So, the solution is:
(3 square root of 2 , 135°), (-3 square root of 2 , 315°)
Answer:
450 students
Step-by-step explanation:
Let s = number of students
1/2 are Americans 1/2s are Americans
s -1/2s = number of students left
1/2 s = number of students left
1/3 of the students left are Europeans
1/3 (1/2s) = 1/6s are Europeans
The rest are Australians = 150
Students = Americans + Europeans + Australians
s = 1/2s + 1/6s + 150
Combine like terms
s = 1/2*3/3 *s + 1/6s +150
s = 3/6s + 1/6s +150
s = 4/6s + 150
Subtract 4/6s from each side
s -4/6s = 150
6/6s - 4/6s = 150
2/6s = 150
1/3s = 150
Multiply each side by 3
3* 1/3s = 150*3
s = 450
There are 450 students