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3 years ago

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A school raises $4,000 for its new library. 36% of that money is used to buy reference books. How much money is used to buy refe

rence books?
__Part ___Whole __New Whole

Solve it: Use a proportion to solve the problem.

1 answer:

Ymorist [56]3 years ago

6 0

Can u show me an example so I could do this foru

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Consider functions f and g below.

Scrat [10]

Answer: -12 x^2 - 3x + 27

In this question, there are two function of f(x) and g(x)
f(x)= -9 x^2 - 7x + 12
g(x)= 3x^2 -4x -15
The question is about f(x)- g(x). To answer this, you just need to replace the question with the function. Don't forget to apply the minus to all the product inside the function. The calculation would be:

f(x)- g(x)=
(-9 x^2 - 7x + 12) -(3x^2 -4x -15)=
-9 x^2 - 7x + 12 (-3x^2 +4x +15)=
-12 x^2 - 3x + 27

5 0

2 years ago

Read 2 more answers

What is the expression in radical form?<br><br> (4x3y2)310

sertanlavr [38]

Given:

Consider the given expression is

$(4x^3y^2)^{\frac{3}{10}}$

To find:

The radical form of given expression.

Solution:

We have,

$(4x^3y^2)^{\frac{3}{10}}=(2^2)^{\frac{3}{10}}(x^3)^{\frac{3}{10}}(y^2)^{\frac{3}{10}}$

$(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{6}{10}}(x)^{\frac{9}{10}}(y)^{\frac{6}{10}}$

$(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{3}{5}}(x)^{\frac{9}{10}}(y)^{\frac{3}{5}}$

$(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{2^3}\sqrt[10]{x^9}\sqrt[5]{y^3}$ $[\because x^{\frac{1}{n}}=\sqrt[n]{x}]$

$(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{8y^3}\sqrt[10]{x^9}$ $[\because x^{\frac{1}{n}}=\sqrt[n]{x}]$

Therefore, the required radical form is $\sqrt[5]{8y^3}\sqrt[10]{x^9}$ .

8 0

3 years ago

The fish Anastasia caught was Plz Help ASAP 20 POINTS

s344n2d4d5 [400]

difference= 0.78[Anastasia's] - (1 - 0.34)[Sergei's]=

0.78m - (0.66m)=0.12m=12cm

6 0

2 years ago

Read 2 more answers

The distribution of heights for adult men in a certain population is approximately normal with mean 70 inches and standard devia

KengaRu [80]

Answer:

The interval (meassured in Inches) that represent the middle 80% of the heights is [64.88, 75.12]

Step-by-step explanation:

I beleive those options corresponds to another question, i will ignore them. We want to know an interval in which the probability that a height falls there is 0.8.

In such interval, the probability that a value is higher than the right end of the interval is (1-0.8)/2 = 0.1

If X is the distribuition of heights, then we want z such that P(X > z) = 0.1. We will take W, the standarization of X, wth distribution N(0,1)

$W = \frac{X-\mu}{\sigma} = \frac{X-70}{4}$

The values of the cumulative distribution function of W, denoted by $\phi$ , can be found in the attached file. Lets call $y = \frac{z-70}{4}$ . We have

$0.1 = P(X > z) = P(\frac{X-70}{4} > \frac{z-70}{4}) = P(W > y) = 1-\phi(y)$

Thus

$\phi(y) = 1-0.1 = 0.9$

by looking at the table, we find that y = 1.28, therefore

$\frac{z-70}{4} = 1.28\\z = 1.28*4+70 = 75.12$

The other end of the interval is the symmetrical of 75.12 respect to 70, hence it is 70- (75.12-70) = 64.88.

The interval (meassured in Inches) that represent the middle 80% of the heights is [64.88, 75.12] .

8 0

2 years ago

10) Which two ratios form a proportion? A) 1 : 2 and 4 : 2 B) 1 : 2 and 6 : 3 C) 2 : 1 and 2 : 4 D) 2 : 1 and 6 : 3

Likurg_2 [28]

Answer:

2/1and6/3 because if you do cross multilication they both equal 6

Step-by-step explanation:

8 0

3 years ago