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professor190 [17]
3 years ago
6

Find the greatest common factor of the following monomials 26n5 12n2

Mathematics
1 answer:
Sidana [21]3 years ago
8 0

The greatest common factor is 2n^{2}


We first have to look for the largest number that goes into both equations. The factors of 12 are 1, 2, 3, 4, 6 and 12. None of 3, 4, 6, or 12 go into 26 evenly. So 2 is the largest number you can take out.


With the variables, we take out as many as the lowest number will let us. Since the smallest number of n's is 2 in the second term, we take that many.

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To find:

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Solution:

Hypotenuse of QSR = QT + TR

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Geometric mean of similar right triangle formula:

$\frac{\text { hypotenuse }}{\text { leg }}=\frac{\text { leg }}{\text { part }}$

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Do cross multiplication.

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