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3 years ago

Is this right?......

Mathematics

2 answers:

masya89 [10]3 years ago

5 0

No It Is A Square pyramid

Kitty [74]3 years ago

4 0

No, the correct answer is square pyramid

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Which expression is equivalent to 3y+4+y

Colt1911 [192]

The answer to this question is 4y+4

8 0

2 years ago

Use the given graph of f to state the value of each quantity, if it exists. (If an answer does not exist, enter DNE.)

alex41 [277]

Answer:

Hence the answer is given as follows,

Step-by-step explanation:

Graph of y = f(x) given,

(a) $\lim_{x\rightarrow 2^{-}}f(x)=3$

(b) $\lim_{x\rightarrow 2^{+}}f(x)=1$

(c) $\lim_{x\rightarrow 2}f(x)= DNE \left \{ \therefore \lim_{x\rightarrow 2^{-}} f(x)\neq \lim_{x\rightarrow 2^{+}}f(x) \right.$

(d) $f(2)=3$

(e) $\lim_{x\rightarrow 4}f(x) = 4$

(f) $f(4)= DNE.$ { Hole in graph}

Hence solved.

3 0

2 years ago

X^2+3x−10=0 (solve for x)

kap26 [50]

Answer:

x1=2 x2=-5

Step-by-step explanation:

7 0

2 years ago

Points A, B and C lie on a circle, centre O.<br> Angle AOC = 142°.<br> Find the value of y.

aksik [14]

The value of the angle $y$ within the quadrilateral $OABC$ inscribed the circle is 142°.

Let suppose that quadrilateral $OABC$ is a parallelogram. Then, the following conditions must be fulfilled:

$\overline {OA} \cong \overline {BC}$
$\overline{AB} \cong \overline{OC}$
$\angle AOC \cong \angle ABC$

In addition, if we have a rhombus we have the additional condition as A, B and C lie on the circle:

$\overline{OA} \cong \overline {AB} \cong \overline {BC} \cong \overline{OC}$ (4)

If we know that $\angle AOC = 142^{\circ}$ , then the value of $\angle ABC = y = 142^{\circ}$ .

Based on all these finding, we conclude that the value of the angle $y$ within the quadrilateral $OABC$ inscribed the circle is 142°.

To learn more on parallelograms, we kindly invite to check this verified question: brainly.com/question/555469

5 0

2 years ago

How to integrate with steps:<br><br> (4x2-6)/(x+5)(x-2)(3x-1)

joja [24]

$\displaystyle\int\frac{4x^2-6}{(x+5)(x-2)(3x-1)}\,\mathrm dx$

You have a rational expression whose numerator's degree is smaller than the denominator's. This tells you you should consider a partial fraction decomposition. We want to rewrite the integrand in the form

$\dfrac{4x^2-6}{(x+5)(x-2)(3x-1)}=\dfrac a{x+5}+\dfrac b{x-2}+\dfrac c{3x-1}$

$\implies4x^2-6=a(x-2)(3x-1)+b(x+5)(3x-1)+c(x+5)(x-2)$

You can use the "cover-up" method here to easily solve for $a,b,c$ . It involves fixing a value of $x$ to make 2 of the 3 terms on the right side disappear and leaving a simple algebraic equation to solve for the remaining one.