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GrogVix [38]
3 years ago
7

How is an isosceles trapezoid and a rhombus the same?

Mathematics
1 answer:
KATRIN_1 [288]3 years ago
7 0
They are the same because they both have 4 sides
You might be interested in
5. In the triangle ABC. M is the midpoint of [AB] and N is the midpoint of [CM].
sweet [91]

Answer:

N(2,3)

Step-by-step explanation:

According to the Question,

  • Given that, In the triangle ABC. M is the midpoint of AB and N is the midpoint of CM And A(-1, 3), B(7-3) and C(1,6).
  • Thus, For coordinates of N. first We have to find the Coordinate of M(x,y). As Given M is the Midpoint of A(-1, 3) and B(7-3).

Thus, M(x,y) = (-1+7)/2 , (3-3)/2 ⇒ M(3,0)

  • Now, As Given, N(a,b) is the Midpoint Of C(1,6) and M(3,0).

Thus. N(a,b) = (1+3)/2 , (6+0)/2  ⇒ N(2,3)

8 0
3 years ago
Let f(x)=6x+7 and g(x)=8x+2, and find the following <br> (Fog)(-3)<br> Answer please
andrezito [222]
G( - 3 ) = 8 * ( - 3 ) + 2 = -24 + 3 = - 21 ;
( fog )(-3) = f( g(-3) ) = f( - 21 ) = 6 * ( -21 ) + 7 = - 126 + 7 = - 119
8 0
4 years ago
How do i do this?....... ​
iris [78.8K]

Order of operations (from high priority to low priority):

Parentheses

Exponents

Multiplications/Division

Addition/Subtraction

All in left to right.

2 ÷ (5 + 3)⁻¹ ÷ 4

2 ÷ (8)⁻¹ ÷ 4

2 ÷ 1/8 ÷ 4

16 ÷ 4

= 4

3 0
3 years ago
Read 2 more answers
Assume you got a temporary job in the payroll department of your local grocery store. It is your job to compute the employees' p
astra-53 [7]

Answer: The answer is $698.00

Step-by-step explanation: For example, if you are receiving SSI and make $200 per month in earned income, the deduction will be made like this: $200 – 20 = $180 – 65 = $115.00/2 = $57.50 Meaning $57.50 would be deducted from the maximum SSI payment of $698.00 month.

Pls mark me as brainiest

4 0
2 years ago
Find the directional derivative of f(x,y,z)=2z2x+y3f(x,y,z)=2z2x+y3 at the point (−1,4,3)(−1,4,3) in the direction of the vector
Feliz [49]

f(x,y,z)=2z^2x+y^3

f has gradient

\nabla f(x,y,z)=2z^2\,\vec\imath+3y^2\,\vec\jmath+4xz\,\vec k

which at the point (-1, 4, 3) has a value of

\nabla f(-1,4,3)=18\,\vec\imath+48\,\vec\jmath-12\,\vec k

I'm not sure what the given direction vector is supposed to be, but my best guess is that it's intended to say \vec u=15\,\vec\imath+25\,\vec\jmath, in which case we have

\|\vec u\|=\sqrt{15^2+25^2}=5\sqrt{34}

Then the derivative of f at (-1, 4, 3) in the direction of \vec u is

D_{\vec u}f(-1,4,3)=\nabla f(-1,4,3)\cdot\dfrac{\vec u}{\|\vec u\|}=\boxed{\dfrac{294}{\sqrt{34}}}

4 0
3 years ago
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